All categories

2 years ago

Pls help i'm lost il give brainly

Mathematics

2 answers:

OverLord2011 [107]2 years ago

4 0

Answer:

Step-by-step explanation:

A= 16 degrees

B= -8 degrees

C= 6 degrees

D= -16 degrees

E= -4 degrees

Advocard [28]2 years ago

3 0

Answer:

a= 16

b= -8

c= 6

d= -16

e= -4

Step-by-step explanation:

You might be interested in

An object falls freely in a straight line and experiences air resistance proportional to its? speed; this means its acceleration

KiRa [710]

Answer:

t = 1.068 s

Step-by-step explanation:

given,

a(t) =- k v(t)

speed of the object decreases from 800 ft/s to 700 ft/s

distance = 1400 ft

time for deceleration = ?

a(t) =- k v(t)

$\dfrac{dv}{dt}= - kv$

$\dfrac{dv}{v}= - kdt$

integrating both side

$\int_{800}^{700}\dfrac{dv}{v}= - k\int dt$

$ln(\dfrac{7}{8})=-kt$

$t = -\dfrac{1}{k}ln(\dfrac{7}{8})$ ..........(1)

since,

$v = v_1e^{-kt}$

$\dfrac{ds}{dt} = 800e^{-kt}$

$\int ds= 800\int_0^t e^{-kt}dt$

$1400= -\dfrac{800}{k}[e^{-kt}-e^0]$

from equation 1

$k= -\dfrac{8}{14}[\dfrac{7}{8}-1]$

$k= \dfrac{1}{8}$

putting value of k in equation (1)

$t = -8ln(\dfrac{7}{8})$

t = 1.068 s

5 0

3 years ago

A. Complete the chart based on the initial conditions:

Nata [24]

Answer:

$Month\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Pop(whole \ ant)\\month1 => x_1=80\times0.94^1=1128\\month2=>x_2=1200\times0.94^2=1060\\month3=>x_3=1200\times0.94^3=996\\month4=>x_4=1200\times0.94^4=936$

$week Number\ \ \ \ \ \ \ \ \ \ \ \ \ \ Mass(g)\\week1 => x_1=80\times1.1^1=88g\\week2=>x_2=80\times1.1^2=96.8g\\week3=>x_3=80\times1.1^3=106.48g\\week4=>x_4=80\times1.1^4=117.128g$

Step-by-step explanation:

a. From the information provided, we can deduce that the population death's follows a Geometric sequence in the form $(a,ar,ar^2,ar^3...)$ where $a-first \ term$ and $r-common \ ratio$

#Since the population is reducing, $r$ can is obtained as $r=1-r=0.94$

#The $n^t^h$ term is obtained using the formula $x_n=ar^(^n^-^1^)$ , given a=1200

The number of ants alive after every month (in first 4 months)

The ant's alive after 4 months is obtained as the value of $x_5$

$x_n=ar^(^n^-^1^)\\1-x_5=1-1200\times 0.94^4=936.89\\\approx 936$

Hence, 936 ants are alive after 4 months.

b. As with the above question, the kitten population follows a geometric sequence: $(a,ar,ar^2,ar^3...)$ .

#Since it's a growing population , the common ration is the sum of 100% + the growth rate,

$r=1.1$ and $a=80$ and $x_n=ar^(^n^-^1^)$

The population after 4weeks will be:

$week Number\ \ \ \ \ \ \ \ \ \ \ \ \ \ Mass(g)\\week1 => x_1=80\times1.1^1=88g\\week2=>x_2=80\times1.1^2=96.8g\\week3=>x_3=80\times1.1^3=106.48g\\week4=>x_4=80\times1.1^4=117.128g$

8 0

3 years ago

For the triangles to be congruent by SSS, what must be the value of x? 1 3 6 8

Brut [27]

Answer:it’s 6

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

when making a peanut butter and jelly sandwich, 96% of people put the peanut butter on first. write 96% as a decimal.

ikadub [295]

Drop the percent sign so that you only have 96 then divide by 100 to get the decimal (or move the decimal place to the left two).

96% --- drop the percent
96 ----- move the decimal place over to or divide by 100

96/100
96.0

.96

3 0

2 years ago

Read 2 more answers

What is the value of x?<br><br> x= <br> units

attashe74 [19]

By Pythagoras theorem

$RQ^{2}= x^{2} + 16^{2}$
$RS^{2}= x^{2} + 9^{2}$

$SQ^{2}= RS^{2} + RQ^{2}$
$SQ^{2}= x^{2} + 16^{2} + x^{2} + 9^{2}$
$SQ^{2}=2 x^{2} +256+81$
$25^{2}=2 x^{2} +337$
$625-337=2 x^{2}$
$288=2 x^{2}$
$144= x^{2}$
$x=12$

8 0

3 years ago

Read 2 more answers