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Blababa [14]
3 years ago
13

In a right triangle the length of a hypotenuse is c and the length of one leg is a, and the length of the other leg is b, what i

s the value of b, if
a=2sqrt3 , c=2b ?

Mathematics
2 answers:
rosijanka [135]3 years ago
5 0

Answer: b = √6

Step-by-step explanation: Use the Pythagorean Theorem to solve this.

a² + b² = c²

Plug in your values:

2√3² + b² = 2b²

When a square root is squared, the square root is cancelled out so you will be left with this:

2(3) + b² = 2b²

Subtract b² from both sides so you’re left with:

6 = b²

Now, to get rid of the square, just square root both sides:

√6 = √b²

Since the √6 is not a perfect square, leave it in the radical. Then, you get your answer:

b = √6

Shalnov [3]3 years ago
4 0

Answer:

the answer:b is equivalent to 2

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7 0
2 years ago
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Suppose you hit a fly ball with an initial upward velocity of 20 feet per second. Which of the following equations would be a re
baherus [9]
A=g≈-32

v=⌠a dt  since a≈-32

v=-32t+C, where C is the initial velocity, which we are told is 20 ft/s

v=-32t+20

h=⌠v dt

h=-32t^2/2+20t+C, where C is the initial height, so what is a reasonable initial height?  How about 3 ft since we are swinging a bat around maybe our waist level... maybe :P

h=-16t^2+20t+3

Your choices may have made a different assumption about the initial height of course but you did not show your choices, but certainly it will be:

h(t)=-16t^2+20t+hi, where hi is the initial height in feet.

This of course ignores air resistance and flight dynamics of a spinning ball with seams, which will make a significant difference in real life :)
3 0
3 years ago
Read 2 more answers
Mia is making costumes for a play. Each costume needs 3 7/9 yards of fabric. If Mia is making 6 costumes, how much fabric does s
mihalych1998 [28]
If she is making 6 costumes that need 3 7/9 yards each, the equation would be 6 x 3 7/9.

The answer to that equation would be 22 2/3.

How to get the answer:
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42/9 = 4 2/3

then add the eight teen and the 4 2/3 and you get 22 2/3.
3 0
2 years ago
Robin has triple as many marbles Amy. Sam has 15 more marbles than robin. Together they all have 99 marbles. How many marbles do
tigry1 [53]
Let:     x be Amy's marbles
         3x be Robin's marbles
   15+3x be Sam's marbles
x+3x+15+3x=99
          7x+15=99
                7x=99-15 (transfer 15 to the right side of the equation, then minus)
             7x/7=84/7 (divide both sides of the equation by 7)
                  x=12
Now substitute:
                             x = 12 (Amy's)
                3x = 3*12 = 36 (Robin's)
   15+3x  = 15+3*12 =  51 (Sam's)
               12+36+51 = 99
Therefore, Amy has 12 marbles, Robin has 36 marbles and Sam has 51 marbles.
5 0
3 years ago
Your math grade is a 68%.You turn in some late work, and now your grade is an 82%.What is the percent change?
Alex

Answer:

your grade increased by 14%

7 0
2 years ago
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