Question

A horizontal line includes the points (0, -2) and (3, -2). Find the slope of the line.

Answer 1

Answer:

We conclude that the slope of the line containing the points (0, -2) and (3, -2) is:

• $m = 0$

Step-by-step explanation:

Given that the line includes the points

• (0, -2)

• (3, -2)

We need to find the slope of the line containing the points between (0, -2) and (3, -2) using the formula

$m=\frac{y_2-y_1}{x_2-x_1}$

where m is the slope between (x₁, y₁) and (x₂, y₂)

In our case,

• (x₁, y₁) = (0, -2)

• (x₂, y₂) = (3, -2)

now substituting (x₁, y₁) = (0, -2) and (x₂, y₂) = (3, -2) in the slope formula

$m=\frac{y_2-y_1}{x_2-x_1}$

$m=\frac{-2-\left(-2\right)}{3-0}$

$m=\frac{-2+2}{3}$

$m=\frac{0}{3}$

$m = 0$

Therefore, we conclude that the slope of the line containing the points (0, -2) and (3, -2) is:

• $m = 0$