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AleksandrR [38]
2 years ago
9

What is the volume of a hemisphere with a diameter of 47.7in, rounded to the nearest tenth of a cubic inch

Mathematics
1 answer:
Reptile [31]2 years ago
5 0

Answer:

28413.4 in (radius} = diameter divided by 2 = 47.7 divided by 2 =23.85

radius=  2

diameter

​ =  2

47.7

=23.85

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There are 3 times as many children as adults at the zoo. Complete the table with possible combinations of adults and children an
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Answer:

Step-by-step explanation:

Adults = x, Children =y

3y=x

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2 years ago
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Which student factored the expression x3 - 3x + x2 - 3 correctly based on their answer below?
VladimirAG [237]
<span>x3 - 3x + x2 - 3 

= x^3 + x^2 - 3x - 3

= (x^3 + x^2) - (3x + 3)

= x^2(x + 1) - 3(x + 1)

= (x^2 -3)(x + 1) = (x + 1)(x2 - 3)

so ans is Roger

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3 years ago
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A large cable company reports the following:
Step2247 [10]

Answer:

P(Cable\ TV\ only) = 50\%

P(Internet\ |\ cable\ TV) = 31.25\%

P(exactly\ 2\ services) = 23\%

P(Internet\ and\ cable\ TV \only) = 23\%

Step-by-step explanation:

Given

Cable\ TV = 80\%

Internet = 44\%

Telephone = 29\%

Cable\ TV\ and\ Internet = 25\%

Cable\ TV\ and\ Telephone = 20\%

Internet\ and\ Telephone = 23\%

All\ Services = 15\%

Solving (a): A) P(cable TV only).

First, we calculate n(cable TV only)

This is calculated as:

n(cable\ TV\ only) = (Cable\ TV) - (Cable\ TV\ and\ Internet) - (Cable\ TV\ and\ Telephone) + (All\ Services)

n(cable\ TV\ only) = 80\% - 25\% - 20\% + 15\%

n(cable\ TV\ only) = 50\%

The probability is:

P(Cable\ TV\ only) = \frac{n(Cable\ TV\ only)}{100\%}

P(Cable\ TV\ only) = \frac{50\%}{100\%}

P(Cable\ TV\ only) = 50\%

Solving (b): P(Internet | cable TV).

This is calculated as:

P(Internet\ |\ cable\ TV) = \frac{Cable\ TV\ and\ Internet}{Cable\ TV}

P(Internet\ |\ cable\ TV) = \frac{25\%}{80\%}

P(Internet\ |\ cable\ TV) = \frac{25}{80}

P(Internet\ |\ cable\ TV) = 31.25\%

Solving (c): P(exactly 2 services).

This is calculated as:

P(exactly\ 2\ services) = (Cable\ TV\ and\ Internet - All) + (Cable\ TV\ and\ Telephone - All) + (Internet\ and\ Telephone - All)

P(exactly\ 2\ services) = (25\% - 15\%) + (20\% - 15\%) + (23\%-15\%)

P(exactly\ 2\ services) = (10\%) + (5\%) + (8\%)

P(exactly\ 2\ services) = 23\%

Solving (d): P(Internet and cable TV only).

This is calculated as:

P(Internet\ and\ cable\ TV \only) = \frac{(Internet\ and\ cable\ TV \only)}{100\%}

P(Internet\ and\ cable\ TV \only) = \frac{23\%}{100\%}

P(Internet\ and\ cable\ TV \only) = \frac{23\%}{1}

P(Internet\ and\ cable\ TV \only) = 23\%

4 0
2 years ago
Two fish are put in a man-made lake with no other fish in it. Each month, the fish population triples. Which model and equation
aleksandr82 [10.1K]

Answer:

Step-by-step explanation:

The basic model for this growth is the exponential function:  y = a(b)^c, where a is the initial value, b is the growth rate and c is the time.

Here we have P = fish population = (2 fish)(3)^t

8 0
3 years ago
Ariel has a standard deck of 52 cards. She draws one card from the deck and then replaces it. She then draws a second card from
BaLLatris [955]
A) probability of sequences can be calculated by multiplying the probability of the first event by the second, etc. until the end of the series. Thirteen cards are clubs in a 52 card deck, so the initial probability of drawing a club is 13/52, or 0.25 (25%). This means that the cumulative probability is 0.25 x 0.25, or 0.0625 (6.25%).

B) Like part a, the initial probability of finding a green marble is 6/16, or 0.375 (37.5%). When not replacing the marble, the second probability is now 5/15, or 0.33 (33.3%), due to the loss of this marble. This means that the cumulative probability is 0.375 x 0.333, or 0.1249 (12.49%).

C) The initial probability of finding a green apple is 4/6, or 0.66 (66.6%). The second probability, when not replacing the apple is now 2/5, or 0.4 (40%) - the loss of the apple affected the total number of apples, but didn’t affect the number of red apples. This means that the cumulative probability is 0.666 x 0.4, or 0.266 (26.6%).

D) Unfortunate, I don’t know what the problem is asking, so I can’t answer this for you.
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2 years ago
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