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IrinaVladis [17]
4 years ago
13

Need help with geometry, probability question. Will award Brainliest (question attached)

Mathematics
2 answers:
tekilochka [14]4 years ago
8 0

Answer:

A and D

Reasoning:

If you look at the different values, you can see that only A and D can be correct answers.

Greeley [361]4 years ago
6 0

Answer:

a and d because they fit the best in the equation

Step-by-step explanation:

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Number 3 please , thanks!
Doss [256]
The inequality would be 34 > 2 x 3, if I'm correct. I'm not to sure on the graph part though , sorry.
4 0
3 years ago
Find the area of the right triangle
xenn [34]

Answer:

Area: 24 sq units

Step-by-step explanation:

Area of a rectangle formula:

A = 0.5bh

Given:

b = 6

h = 8

Work:

A = 0.5bh

A = 0.5(6)(8)

A = 3(8)

A = 24

3 0
3 years ago
Read 2 more answers
The probability of contamination in batch 1 of a drug (event A) is 0.16, and the probability of contamination in batch 2 of the
VLD [36.1K]
We have:
Event A ⇒ P(A) = 0.16
Event B ⇒ P(B) = 0.09
Probability of event B given event A happening, P(B|A) = P(A∩B) / P(A) = 0.12

By the conditional probability, the probability of event A and event B happens together is given by:
P(B|A) = P(A∩B) ÷ P(A)
P(B|A) = P(A∩B) ÷ 0.16
0.12 = P(A∩B) ÷ 0.16
P(A∩B) = 0.12 × 0.16
P(A∩B) = 0.0192

When two events are independent, P(A) × P(B) = P(A∩B) so if P(A∩B) = 0.0192, then P(B) will be 0.0192 ÷ 0.16 = 0.12 (which take us back to P(B|A))

Since P(B|A) does not equal to P(B), event A and event B are not independent.

Answer: <span>Events A and B are not independent because P(B|A) ≠ P(B)</span>

4 0
4 years ago
Please help!! ASAP
Kryger [21]

Answer:

The answer is 117.3 in^{3}.

Step-by-step explanation:

To solve for the volume of the cone, use the cone volume formula, which is   V = \frac{1}{3} \pi  r^{2} h.

Next, plug in the information given from the problem, and the formula will look like V = \frac{1}{3} (\pi) (4 in^{2}) (7 in).

Then, solve the equation, and the answer will be 117.3 in^{3}.

6 0
3 years ago
There are values of t so that sin t=.35 and cos t=.6
NISA [10]

Recall the fundamental rule of trig:

\sin^2(x)+\cos^2(x)=1 \quad\forall x \in \mathbb{R}

So, there exists an angle t such that

(0.6,0.35)=(\sin(t),\cos(t))

if and only if

\sin^2(t)+\cos^2(t)=0.6^2+0.35^2=1

Working out the numbers, we get

0.6^2+0.35^2=0.36+0.1225=0.4825\neq 1

So, there doesn't exist a number t such that

(0.6,0.35)=(\sin(t),\cos(t))

7 0
3 years ago
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