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Maru [420]
3 years ago
15

Can someone please help me with number 22?

Mathematics
2 answers:
kobusy [5.1K]3 years ago
6 0
I agree, I think what you're looking for is 156.9
daser333 [38]3 years ago
4 0
The answer is 156.9. Because if it is the hiper x-43 and the maxiumum speed is 6750 you need to square root it then divide it.
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ANSWER ASAP ITS FOR FINALS
Roman55 [17]

Answer:

9. 66°

10. 44°

11. 2\sqrt{7}

12. 2\sqrt{3}

13. 27.3

14. 33.9

15. 22°

16. 24°

Step-by-step explanation:

9. Add 120 + 80 (equals 200) and subtract that from 360 (Because all angles in a quadrilteral add to 360°), this equals 160. Plug the same number in for both variables in the two other angle equations until the two angles add to 160. For shown work on #9, write:

120 + 80 = 200

360 - 200 = 160

12(5) + 6 = 66°

19(5) - 1 = 94°

94 + 66 = 160

10. Because the two sides are marked as congruent, the two angles are as well. This means the unlabeled angle is also 68°. The interior angles of a triangle always add to 180°, so add 68+68 (equals 136) and subtract that from 180, this equals 44. For shown work on #10, write:

68 x 2 = 136

180 - 136 = 44

11. Use the Pythagorean theorem (a² + b² = c²) (Make sure to plug in the hypotenuse for c). Solve the equation. For shown work on #10, write:

a² + b² = c²

a² + 6² = 8²

a² + 36 = 64

a² = 28

a = \sqrt{28}

a = 2\sqrt{7}

12. (Same steps as #11) Use the Pythagorean theorem (a² + b² = c²) (Make sure to plug in the hypotenuse for c). Solve the equation. For shown work on #11, write:

a² + b² = c²

a² + 2² = 4²

a² + 4 = 16

a² = 12

a = \sqrt{12}

a = 2\sqrt{3}

13. Use SOH CAH TOA and solve with a scientific calculator. For shown work on #13, write:

Sin(47°) = \frac{20}{x}

x = 27.3

14. Use SOH CAH TOA and solve with a scientific calculator. For shown work on #14, write:

Tan(62°) = \frac{x}{18}

x = 33.9

15. Use SOH CAH TOA and solve with a scientific calculator. For shown work on #15, write:

cos(θ) = 52/56

θ = cos^-1 (0.93)

θ = 22°

16. (Same steps as #15) Use SOH CAH TOA and solve with a scientific calculator. For shown work on #16, write:

sin(θ) = 4/10

θ = sin^-1 (0.4)

θ = 24°

Good luck!!

8 0
3 years ago
Y=(2x-3)^5(2-x^4)^3 differentiate the function please
BARSIC [14]
\bf y=(2x-3)^5(2-x^4)^3\\\\
-------------------------------\\\\
\cfrac{dy}{dx}=\stackrel{\textit{product rule}}{[5(2x-3)^4\cdot 2(2-x^4)3]~~+~~[(2x-3)^5[3(2-x^4)^2(-4x^3)]]}
\\\\\\
\cfrac{dy}{dx}=10(2x-3)^4(2-x^4)^3~~-~~12x^3(2x-3)^5(2-x^4)^2
\\\\\\
\cfrac{dy}{dx}=\stackrel{\textit{common factor}}{2(2x-3)^4(2-x^4)^2}~[5(2-x^4)-6x^3(2x-3)]
\\\\\\
\cfrac{dy}{dx}=2(2x-3)^4(2-x^4)^2~[10-5x^4-12x^4+18x^3]
\\\\\\
\cfrac{dy}{dx}=2(2x-3)^4(2-x^4)^2(10-17x^4+18x^3)
5 0
3 years ago
Find the square root of 146.00048648 up to three places of decimal?
aivan3 [116]
Answer:

12.083

Explanation:

Plug into a calculator.
3 0
3 years ago
HELLLLLLP ME EEEEEEEE​
andrew11 [14]

Answer:

A. y=3x  but 3 is the slope

hope this helps

have a good day :)

Step-by-step explanation:

5 0
3 years ago
Solve using algebraic equation: <br> 5sin2x=3cosx<br><br> (No exponents)
DaniilM [7]
5\sin2x=3\cos x\iff10\sin x\cos x=3\cos x

by the double angle identity for sine. Move everything to one side and factor out the cosine term.

10\sin x\cos x=3\cos x\iff10\sin x\cos x-3\cos x=\cos x(10\sin x-3)=0

Now the zero product property tells us that there are two cases where this is true,

\begin{cases}\cos x=0\\10\sin x-3=0\end{cases}

In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of \dfrac\pi2, so x=\dfrac{(2n+1)\pi}2 where n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}

which occurs twice in the interval [0,2\pi) for x=\arcsin\dfrac3{10} and x=\pi-\arcsin\dfrac3{10}. More generally, if you think of x as a point on the unit circle, this occurs whenever x also completes a full revolution about the origin. This means for any integer n, the general solution in this case would be x=\arcsin\dfrac3{10}+2n\pi and x=\pi-\arcsin\dfrac3{10}+2n\pi.
6 0
3 years ago
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