Answer is steel and aluminum.
Answer:
B.) and D.)
Explanation:
A.) is incorrect because the reaction technically never stops if the system remains in tact. Rather, there is just an equal amount of forward and reverse reactions occurring. This means that the overall concentrations of the reactants and products stays the same.
B.) is correct because when the concentrations of the reactants and products remain unchanged, then equilibrium is reached.
C.) in incorrect because, at this point, the concentrations of the reactants are still decreasing and the products are still increasing. If point 2 is specifically referencing the intersection of the lines, this cross symbolizes equal concentrations of the reactants and product. Keep in mind that equal concentrations does not equal equilibrium.
D.) is correct because a reaction moving forward means that mostly product is being created. In other words, the concentration of the product should be increasing. Meanwhile, the concentration of the reactants decrease because they are being used to create the product. As seen in the graph, the product (H₂O₂) is rapidly increasing in concentration. Meanwhile, the concentrations of the reactants (O₂ and H₂O) are decreasing as they would in a forward reaction.
Answer:
Here's what I get
Explanation:
You want to dilute the original solution by a factor of 25 in two steps, so you could dilute it by a factor of 5 in the first step, then dilute the new solution by another factor of 5.
A. First dilution
Use a 10 mL pipet to transfer 10 mL of the original solution to a 50 mL volumetric flask. Make up to the mark with distilled water. Shake well to mix.
Use the dilution formula to calculate the new concentration.
B. Second dilution
Repeat Step 1, using the 0.003 970 mol·L⁻¹ solution.
3. Check:
Compare the final concentration with the original
Answer:
8.2763 g
Explanation:
Considering the Henderson- Hasselbalch equation for the calculation of the pH of the buffer solution as:
pH=pKa+log[base]/[acid]
Where Ka is the dissociation constant of the acid.
Given that the acid dissociation constant = 3.5×10⁻⁸
pKa = - log (Ka) = - log (3.5×10⁻⁸) = 7.46
Given concentration of acid = [acid] = 0.244 M
pH = 6.733
So,
6.733 = 7.46+log[base]/0.244
[Base] = 0.0457 M
Given that Volume = 2 L
So, Moles = Molarity × Volume
Moles = 0.0457 × 2 = 0.0914 moles
Molar mass of potassium hypochlorite = 90.55 g/mol
Mass = Moles × Molar mass = (0.0914 × 90.55) g = <u>8.2763 g</u>
Answer: Qualitative
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