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kow [346]
3 years ago
6

How many grams of solid potassium hypochlorite should be added to 2.00 L of a 0.244 M hypochlorous acid solution to prepare a bu

ffer with a pH of 6.733 ? ka = 3.5×10-8
grams potassium hypochlorite = g.
Chemistry
1 answer:
Olin [163]3 years ago
7 0

Answer:

8.2763 g

Explanation:

Considering the Henderson- Hasselbalch equation for the calculation of the pH of the buffer solution as:

pH=pKa+log[base]/[acid]

Where Ka is the dissociation constant of the acid.

Given that the acid dissociation constant = 3.5×10⁻⁸

pKa = - log (Ka) = - log (3.5×10⁻⁸) = 7.46

Given concentration of acid = [acid] = 0.244 M

pH = 6.733

So,

6.733 = 7.46+log[base]/0.244

[Base] = 0.0457 M

Given that Volume = 2 L

So, Moles = Molarity × Volume

Moles = 0.0457 × 2 = 0.0914 moles

Molar mass of potassium hypochlorite = 90.55 g/mol

Mass = Moles × Molar mass = (0.0914 × 90.55) g = <u>8.2763 g</u>

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6 0
3 years ago
Could volume by displacement be used to determine the volume of a lump of rock salt? Explain would be nice
Readme [11.4K]

Yes it could, but you'd have to set up the process very carefully.
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5 0
3 years ago
What is the balanced form of the following equation?. Br2 + S2O32– + H2O → Br1– + SO42– + H+.
zloy xaker [14]
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so, the answer would be : 

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Hope this helps
8 0
3 years ago
Which of these substances is an example of a solution?
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7 0
3 years ago
Read 2 more answers
. How many grams of NaOH would you need to make 450 mL of a 0.250 M NaOH solution
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You have molarity and you have volume. Use the formula :
Molarity(M)= Moles(N)/Liter(L)            to get the solution. 
450 ml= .450 L
.250 = N/.450
N=.1125 moles of NaOH.
 And since you know the moles, use the molar mass to figure out the grams.
<span> (40g/mol NaOH) x (.1125 mol) =  
4.5g of NaOH.
</span>
Hope it helps. Good luck on chemistry.
7 0
3 years ago
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