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vovikov84 [41]
3 years ago
14

Q3. A student added water to calcium oxide to make calcium hydroxide

Chemistry
1 answer:
galina1969 [7]3 years ago
6 0

26.4 kg of calcium hydroxide (Ca(OH)₂)

Explanation:

We have the following chemical reaction:

CaO + H₂O → Ca(OH)₂

molecular weight of Ca(OH)₂ = atomic mass of Ca × number of Ca atoms + atomic mass of O × number of O atoms + atomic mass of H × number of H atoms

molecular weight of Ca(OH)₂ = 40 × 1 + 16 × 2 + 1 × 2 = 74 g/mole

molecular weight of CaO = atomic mass of Ca × number of Ca atoms + atomic mass of O × number of O atoms

molecular weight of CaO = 40 + 16 = 56 g/mole

number of moles = mass / molecular weight

number of moles of CaO = 20 / 56 = 0.357 kmoles

Taking in account the chemical reaction we devise the following reasoning:

if        1 kmole of CaO produces 1 kmole of Ca(OH)₂

then   0.357  kmoles of CaO produces X kmoles of Ca(OH)₂

X = (0.357 × 1) / 1 = 0.357 kmoles of Ca(OH)₂

mass = number of moles × molecular weight

mass of Ca(OH)₂ = 0.357 × 74 = 26.4 kg

Learn more about:

number of moles

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Explanation:

Formula for black body radiation is as follows.

                 \frac{P}{A} = \sigma \times T^{4} J/m^{2}s

where,       P = power emitted

                 A = surface area of black body

          \sigma = Stephen's constant = 5.6703 \times 10^{-8} watt/m^{2}.K^{-4}

As area is given as 1.0 cm^{2}. Converting it into meters as follows.

           1.00 cm^{2} \times \frac{(10^{-2})^{2} m^{2}}{1 cm^{2}}      (as 1 m = 100 cm)

            = 1 \times 10^{-4} m^{2}

It is given that P = 201 watts. Hence,  

       \frac{201 watts}{1 \times 10^{-4} m^{2}} = 5.6703 \times 10^{-8} watt/m^{2}.K^{-4} \times T^{4}

                T^{4} = 35.45 \times 10^{12}

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Thus, we can conclude that the temperature of the surface is 8862.5 K.

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In an aqueous chloride solution cobalt(ii) exists in equilibrium with the complex ion cocl42-. co2 (aq) is pink and cocl42-(aq)
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First you should know that the Principle of Le Chatelier states that <u>if a system in equilibrium is subjected to a change of conditions, it will move to a new position in order to counteract the effect that disturbed it and recover the state of equilibrium.</u>

The variation of one or several of the following factors can alter the equilibrium condition in a chemical reaction:

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1. This reaction is: <u>a. exothermic</u>

The chemical equilibrium at issue is:

CoCl₄²⁻  ⇄   Co²⁺ + 4Cl⁻ + heat

<em>blue</em>            <em>pink</em>

The reaction of the question is <u>exothermic</u> because when adding heat (at high temperature) the equilibrium moves to the left since the blue color is strong which means that there are more reagent (CoCl₄²⁻) that product (Co²⁺). On the other hand, when extracting heat from the system (at low temperature) the equilibrium moves to the right since the pink color predominates and more product is present in the solution.

2. When the temperature is decreased the equilibrium constant, k: <u>c. remains the same.</u>

As mentioned above, <u>a system in equilibrium that is disturbed will move to a new position in order to counteract the effect that disturbed it and recover the state of equilibrium. </u>In this way, the system will always remain in equilibrium and its equilibrium constant will remain constant. This is why, despite altering the temperature of the system, the equilibrium constant remains constant.

3. When the temperature is decreased the equilibrium concentration of Co²⁺:  <u>a. increases</u>

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Step 2: Calculate the moles corresponding to 1.0 kg of C₈H₁₈.

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The molar mass of CO₂ is 44.01 g/mol.

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