Answer:
mass of 1 mole of 127 grams, KCI, 552mL = 51.1099987g
Explanation:
Answer:
Volume in L = 0.50 L
Explanation:
Given data:
Molarity of solution = 0.1850 M
Mass of BaCl₂ = 19.30 g
Volume of solution = ?
Solution:
First of all we will calculate the number of moles of solute:
Number of moles = mass/molar mass
Molar mass of BaCl₂ = 208.23 g/mol
Number of moles = 19.30 g / 208.23 g/mol
Number of moles = 0.093 mol
Volume of solution:
Molarity = number of moles of solute / volume of solution in L
0.1850 M = 0.093 mol / Volume in L
Volume in L = 0.093 mol / 0.1850 M (M= mol/L)
Volume in L = 0.50 L
Answer:
0.225M
Explanation:
Step 1:
Data obtained from the question. This includes:
Volume of the stock solution (V1) = 125mL
Molarity of the stock solution (M1) = 0.90 M
Volume of the diluted solution (V2) = 125 + 375 = 500mL
Molarity of the diluted solution (M2) =..?
Step 2:
Determination of the molarity of the diluted solution.
This is obtained by using the dilution formula as follow:
M1V1 = M2V2
0.9 x 125 = M2 x 500
Divide both side by 500
M2 = (0.9 x 125) /500
M2 = 0.225M
Therefore, the molarity of the diluted solution is 0.225M
Answer:
No
Explanation:
Bbecause number of w is not equal on both sides
