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marin [14]
4 years ago
8

Find the value of ‘A’ in the set of supplementary angles.

Mathematics
1 answer:
otez555 [7]4 years ago
6 0
Ok, remember that half a circle is always 180 degrees. so..
1. 141
2. 23
3. 88
4. 120
5. 119
6. 152.

And also, want free points?

go tohttps://brainly.com/question/8360353

if you could vote me as the brainiest answer, that would be amazeballs!
hope it helps!
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If zb⊥ya , find m<br><br>A. 28<br><br>B.46<br><br>C.56<br><br>D.62<br><br>I'll give you brainliest
prohojiy [21]
<h3>Answer:</h3>

A. 28

<h3>Step-by-step explanation:</h3>

We assume m is the measure of the marked unknown angles: ∠BZY ≅ ∠BZA

(5x +3)° = (2x +18)°

Divide by ° and subtract 2x+3:

... 3x = 15

... x = 5

Then ∠BZA = (2·5 +18)° = m = 28°

5 0
3 years ago
Does anyone know what 1+1 is?
hammer [34]

1+1 = 2  that is the answer


6 0
3 years ago
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3) Two of these numbers are the same value, which ones are<br> they? 40%, .44, 14, .04, 4/10?
baherus [9]

Answer:

40% and 4/10

Step-by-step explanation:

If you convert them into decimals, they will both give the same decimals which gives 0.4

4 0
3 years ago
Read 2 more answers
What is the value of x<br><br> Triangle with sides 10 6 x-6
Grace [21]
Given that the triangle is a right angled triangle, to solve for x we shall use the Pythagorean theorem given by:
c^2=a^2+b^2
where:
c is the hypotenuse
a and b are the legs.
c=10
a=6
b=(x-6)
thus plugging the values in the equation and solving for x we get:
10^2=6^2+(x-6)^2
100=36+x^2-12x+36
100=x^2-12x+72
0=x^2-12x-28
factoring the above we get:
0=(x+2)(x-14)
hence
x=-2 or x=14
given that there is no negative distance then
x=14
thus the value of x is 14
5 0
4 years ago
What is the inverse of f(x)=x^4+7 for x&gt;0 where function g is the inverse of function f?<br> -
Ann [662]

Answer:

g(x) = \sqrt[4]{x-7},~ x\geq 7

Step by step explanation:

y= f(x) = x^4+7\\\\\text{Replace x with y and solve for y:}\\\\~~~~~~~x = y^4 +7\\\\\implies y^4 = x-7\\\\\implies y = \pm\sqrt[4]{x-7}\\\\ \implies f^{-1}(x) = \pm\sqrt[4]{x-7}

7 0
2 years ago
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