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-BARSIC- [3]
3 years ago
6

Use the svd() function in MATLAB to compute , the rank-1 approximation of . Clearly state what is, rounded to 4 decimal places.

Also, compute the root mean square error (RMSE) between and .
Mathematics
1 answer:
Afina-wow [57]3 years ago
7 0

Answer:

Here is the Matlab code.

Step-by-step explanation:

Matlab Code:

A = [1 2 2;3 4 5;6 7 8]\\[U,S,V] = svd(A)u1 = U(:,1)\\u2 = U(:,2)\\u3 = U(:,3)\\d1 = dot(u1,u2)\\c = cross(u1,u2)\\d2 = dot(c,u3)

d1 =-    5.5511e-17\\c =   -0.7172    0.6643   -0.2103\\d2 =        1  

Yes, since c = cross(u1,u2) is orthogonal to both u1 and u2. Hence is u3, thus the dot product with u3 is 1.

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Now we look for y. So choose one formula from the two (let's say 5x + 3y=58)
Substitute x for 8 so it will look like---- 5(8)+3y=58
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divide both sides by 3
you get y=6
In conclusion, x=8 and y=6 hence, (8,6)


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