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-BARSIC- [3]
3 years ago
6

Use the svd() function in MATLAB to compute , the rank-1 approximation of . Clearly state what is, rounded to 4 decimal places.

Also, compute the root mean square error (RMSE) between and .
Mathematics
1 answer:
Afina-wow [57]3 years ago
7 0

Answer:

Here is the Matlab code.

Step-by-step explanation:

Matlab Code:

A = [1 2 2;3 4 5;6 7 8]\\[U,S,V] = svd(A)u1 = U(:,1)\\u2 = U(:,2)\\u3 = U(:,3)\\d1 = dot(u1,u2)\\c = cross(u1,u2)\\d2 = dot(c,u3)

d1 =-    5.5511e-17\\c =   -0.7172    0.6643   -0.2103\\d2 =        1  

Yes, since c = cross(u1,u2) is orthogonal to both u1 and u2. Hence is u3, thus the dot product with u3 is 1.

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scoundrel [369]
1) The measures of the opposite angles of an inscribed quadrilateral are supplementary, add up to 180.

That means that angle ROP and angle RQP are supplementary.

We can add them and set them equal to 180 so that we can solve for x first.

∠ROP + RQP = 180
x + 17 + 6x - 5 = 180
7x + 12 = 180
7x = 168
x = 24

Now use the 24 for x and solve for the measure of angle ROP.

∠ROP = x + 17
∠ROP = 24 + 17
∠ROP = 41

The answer is A

2) The answer is A.

Hope this helps :)
4 0
3 years ago
Select three ratios that are equivalent to 7: 6.
scZoUnD [109]

Answer:

ratio number 1-  14:12

ratio number 2- 21:18

ratio number 3- 28:24

5 0
3 years ago
Help me pleaseeee I need it
Marta_Voda [28]
4(2x5 + 3) - 4(2) + 2(5).

4(13) - 18.

52-18 = 34.
4 0
3 years ago
Read 2 more answers
A cistern can be completely drained by a pipe in 6 hours. It can be filled by two pipes in 4 hours and 5 hours, respectively. Ho
boyakko [2]
X/4 +x/5 -x/6=1
make the denominator the same: 
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6 0
3 years ago
9. How many gallons of paint will you need to buy if you are painting a room that is 30 ft by
pentagon [3]

Answer:

To paint the room with dimension 30 ft by 50 ft by 50 ft is 26.67 gallon    

Step-by-step explanation:

Given as :

The Length of wall = L = 50 ft

The width of wall   = W = 30 ft

The height of wall  = H = 50 ft

Each gallon of paints should cover 300 sq feet

Let the amount o gallon required to paint the room = x

SO, Area of four wall = 2 × ( L + W ) × H

Or, Area of four wall = 2 × ( 50 + 30 ) × 50

Or, Area of four wall = 2 × ( 80 ) × 50

SO, Area of four wall = 8000  ft²

∵ To paint 300 sq ft the amount of paint required = 1 gallon

∴ To paint 8000 sq ft the amount of paint required = 26.67 gallon

Hence ,to paint the room with dimension 30 ft by 50 ft by 50 ft is 26.67 gallon      answer  

6 0
3 years ago
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