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3 years ago

How many pencils can be purchased with $0.51 if it costs of 8 pencils is $1.36 ?

Mathematics

2 answers:

svp [43]3 years ago

8 0

First year to find how much one pencil cost cost then multiply A number

ICE Princess25 [194]3 years ago

3 0

8 pencil: $1.36
? pencil:$0.51, so 0.51×8÷1.36. As a result, you could buy 3 pencils with $0.51. Hope it help!

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Divide: 7/8 ÷ 3/8 A) 21/64 B) 3/7 C) 64/21 D) 7/3

lozanna [386]

Answer:

When you need to divide two fractions, reverse the second fraction, then multiply the top numbers by each other and the bottom numbers by each other.

7/8 / 3/8 =

7/8 x 8/3 =

(7 x 8) / (8 x 3) =

56/24 which reduces to 7/3

The answer is D) 7/3

5 0

3 years ago

-25-6= -25 + -6 = -31

VashaNatasha [74]

30 + 40 1- 40 = 69

Step-by-step explanation:

4 0

3 years ago

Consider the following differential equation to be solved by undetermined coefficients. y(4) − 2y''' + y'' = ex + 1 Write the gi

kompoz [17]

Answer:

The general solution is

$y= (C_{1}+C_{1}x) e^0x+(C_{3}+C_{4}x) e^x +\frac{1}{2} (e^x(x^2-2x+2)-e^x(2(x-1)+e^x(2))$

+ $\frac{x^2}{2}$

Step-by-step explanation:

Step :1:-

Given differential equation y(4) − 2y''' + y'' = e^x + 1

The differential operator form of the given differential equation

$(D^4 -2D^3+D^2)y = e^x+1$

comparing f(D)y = e^ x+1

The auxiliary equation (A.E) f(m) = 0

$m^4 -2m^3+m^2 = 0$

$m^2(m^2 -2m+1) = 0$

$(m^2 -2m+1) this is the expansion of (a-b)^2$

$m^2 =0 and (m-1)^2 =0$

The roots are m=0,0 and m =1,1

complementary function is $y_{c} = (C_{1}+C_{1}x) e^0x+(C_{3}+C_{4}x) e^x$

Step 2:-

The particular equation is $\frac{1}{f(D)} Q$

P.I = $\frac{1}{D^2(D-1)^2} e^x+1$

P.I = $\frac{1}{D^2(D-1)^2} e^x+\frac{1}{D^2(D-1)^2}e^{0x}$

P.I = $I_{1} +I_{2}$

$\frac{1}{D^2} (\frac{x^2}{2!} )e^x + \frac{1}{D^{2} } e^{0x}$

$\frac{1}{D} means integration$

$\frac{1}{D^2} (\frac{x^2}{2!} )e^x = \frac{1}{2D} \int\limits {x^2e^x} \, dx$

applying in integration u v formula

$\int\limits {uv} \, dx = u\int\limits {v} \, dx - \int\limits ({u^{l}\int\limits{v} \, dx } )\, dx$

$I_{1}$ = $\frac{1}{D^2(D-1)^2} e^x$

$\frac{1}{2D} (e^x(x^2)-e^x(2x)+e^x(2))$

$\frac{1}{2} (e^x(x^2-2x+2)-e^x(2(x-1)+e^x(2))$

$I_{2}$ $= \frac{1}{D^2(D-1)^2}e^{0x}$

$\frac{1}{D} \int\limits {1} \, dx= \frac{1}{D} x$

again integration $\frac{1}{D} x = \frac{x^2}{2!}$

The general solution is $y = y_{C} +y_{P}$

$y= (C_{1}+C_{1}x) e^0x+(C_{3}+C_{4}x) e^x +\frac{1}{2} (e^x(x^2-2x+2)-e^x(2(x-1)+e^x(2))$

+ $\frac{x^2}{2!}$

3 0

3 years ago

P(Q) = 12/17 P(R) = 3/8 If Q and Rare independent events, find the PQ and R).

kodGreya [7K]

Answer:

9/34

Step-by-step explanation:

P(QnR) = P(Q) * P(R)

= 12/17 * 3/8

= 9/34

6 0

2 years ago

The sum of two numbers is 0. Twice the smaller number subtracted from 3 times the larger number is 10. Let x represent th larger

slava [35]

The sum of two numbers is zero.
x + y = 0
y = -x

Twice the smaller number subtracted from 3 times the larger number is 10.
Let x represent the larger number and y represent the smaller number.

Twice the smaller number: 2y

3 times the larger number: 3x

Twice the smaller number subtracted from 3 times the larger number is 10.
3x - 2y = 10

-2y = -3x + 10

y = 3/2 x - 5

The equations are:

y = -x
y = 3/2 x - 5

The answer is the first choice.

5 0

3 years ago

Read 2 more answers