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3 years ago

Find the side of an equilateral traingle whose perimeter is 75 cm

Mathematics

2 answers:

nevsk [136]3 years ago

8 0

Answer:

Each side is 25cm long.

Step-by-step explanation:

75/3=25 (This is because each side of an equilateral triangle is equal to each other.) (The perimeter is all sides added together.)

Ilia_Sergeevich [38]3 years ago

8 0

Answer:

equilateral traingle mean all sides are equal..so 75÷3

=25cm

Step-by-step explanation:

its equal....so we just simply just divide..

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Nolan used the following procedure to find an estimate for StartRoot 18 EndRoot.

stiks02 [169]

Answer:

Nolan correctly identified the square numbers before and after 18.

The square roots of them are 4 and 5.

Clearly, square root of 18 should lie between 4 and 5 only.

He, then carefully squared 4.1, 4.2, 4.3 etc. and identified that 4.3 squared is nearer to 18.

Since, Nolan is finding estimated square root, his steps are cool and he didn't make any error.

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3 years ago

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Answer:

y=1/2x+2(2 is the y-intercept)

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2 years ago

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30 > -6(2X +3)<br> show me how to solve

MA_775_DIABLO [31]

<h3><u>x > -4 is the solution to this inequality.</u></h3>

30 > -6(2x + 3)

Distributive property.

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Divide both sides by -12.

(Because we're dividing by a negative, the inequality sign flips.)

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3 years ago

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At an ocean-side nuclear power plant, seawater is used as part of the cooling system. This raises the temperature of the water t

grandymaker [24]

Answer:

(a1) The probability that temperature increase will be less than 20°C is 0.667.

(a2) The probability that temperature increase will be between 20°C and 22°C is 0.133.

(b) The probability that at any point of time the temperature increase is potentially dangerous is 0.467.

Step-by-step explanation:

Let <em>X</em> = temperature increase.

The random variable <em>X</em> follows a continuous Uniform distribution, distributed over the range [10°C, 25°C].

The probability density function of <em>X</em> is:

$f(X)=\left \{ {{\frac{1}{25-10}=\frac{1}{15};\ x\in [10, 25]} \atop {0;\ otherwise}} \right.$

(a1)

Compute the probability that temperature increase will be less than 20°C as follows:

$P(X$

Thus, the probability that temperature increase will be less than 20°C is 0.667.

(a2)

Compute the probability that temperature increase will be between 20°C and 22°C as follows:

$P(20$

Thus, the probability that temperature increase will be between 20°C and 22°C is 0.133.

(b)

Compute the probability that at any point of time the temperature increase is potentially dangerous as follows:

$P(X>18)=\int\limits^{25}_{18}{\frac{1}{15}}\, dx\\=\frac{1}{15}\int\limits^{25}_{18}{dx}\,\\=\frac{1}{15}[x]^{25}_{18}=\frac{1}{15}[25-18]=\frac{7}{15}\\=0.467$

Thus, the probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c)

Compute the expected value of the uniform random variable <em>X</em> as follows:

$E(X)=\frac{1}{2}[10+25]=\frac{35}{2}=17.5$

Thus, the expected value of the temperature increase is 17.5°C.

7 0

3 years ago

7 - r/8 - 3d <br><br><br><br> Variables <br><br> r=32 and d= 2

satela [25.4K]

The required value if r = 32 and d = 2 is -3

Given the expression

$7-\frac{r}{8} - 3d$

Substituting the given variables

r = 32

d = 2

The expression becomes

$= 7-\frac{32}{8} - 3(2)\\= 7 - 4 - 6\\= 3 - 6\\= -3$

Hence the required value is -3

Learn more here: brainly.com/question/17499155

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2 years ago