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Finger [1]
3 years ago
13

A company makes $300 each month selling its products to the public. The company has $435 in its bank account. How many months of

selling its products to the public was done?
Do any of you have discord?
Mathematics
2 answers:
Stolb23 [73]3 years ago
7 0
Answer:
1 month (and 13 days)
Explanation:
$300 = 1 month
$435 divided by $300 = 1.45
$435 = 1.45 months
You cannot leave a month as a decimal so you should round it to one month when answering the question. If the question asks you to be more specific, write 1 month and 13 days as 45% of one month is 13.
Galina-37 [17]3 years ago
4 0

Answer:

300x = 435, given x represents the amount of months.

So 435 divided by 300 is 1.45 months for that amount.

Step-by-step explanation:

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Zoe is a salesperson who sells computers at an electronics store. She is paid a 1% commission for every computer sale she makes,
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<u>Given:</u>

Zoe gets paid a 1% commission for every sale she makes in addition to base pay.

She sold $8,000 worth of computers on a day and made $140 that day.

<u>To find:</u>

A function P(x) representing total pay on a day where she sells x dollars worth of computers.

<u>Solution:</u>

To determine the function P(x) we need to determine how much Zoe's base pay per day is.

One day, she sold $8,000 worth of computers and made $140 that day.

She gets a commission of 1% for $8,000.

1% of $8,000 = \frac{1}{100} (8,000) = 80.

So she got paid $140 out of which $80 was a commission.

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So Zoe's base pay is $60 a day.

P(x) is the sum of her base pay and 1% of the amount of computer sales she makes ($x).

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3 years ago
What is x, the distance between points A and A'? 2. 4 units 4. 8 units 13. 6 units 14. 4 units.
adelina 88 [10]

The distance between points A (3, -5) and A' (2, -3) is 2.4 units.

Given that,

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According  to the question,

The distance between two points is determined by using the distance formula.

\rm Distance \ formula = \sqrt{(x_2-x_2) ^2+ (y_2-y_2)^2

Then,

The distance between points A (3, -5) and A' (2, -3) is,

\rm Distance  = \sqrt{(2-3) ^2+ ((-3)-(-5))^2}\\\\ Distance  = \sqrt{(-1) ^2+ (2)^2}\\\\ Distance  = \sqrt{1+4}\\\\Distance = \sqrt{5}\\\\Distance = 2.4 \ units

Hence, The distance between points A (3, -5) and A' (2, -3) is 2.4 units.

For more details refer to the link given below.

brainly.com/question/8069952

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Answer:

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