I think it is 5 Bc I do and if you got to know so bad
Answer:
Step-by-step explanation:
DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
<h3>
Congruent shape</h3>
Two shapes are said to be congruent if they have the same shape, all their corresponding angles and sides are congruent to one another.
Given that DE = AB and BC = EF.
In right triangle DEF, using Pythagoras:
DF² = DE² + EF²
Also, In right triangle ABC, using Pythagoras:
AC² = AB² + BC²
But DE = AB and EF = BC, hence:
AC² = DE² + EF²
AC² = DF²
Taking square root of both sides, hence:
AC = DF
Since DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
Find out more on Congruent shape at: brainly.com/question/11329400
Answer:
P = (2, 7)
Step-by-step explanation:
You want to find coordinates of P on segment AB such that P is 3/4 is of the way from A to B.
<h3>Equation for P</h3>
For some fraction q of the distance from A to B, the point P that lies at that fraction of the distance is given by ...
P = A +q(B -A) = (1 -q)A +qB
<h3>Application</h3>
For q = 3/4, the location of P is ...
P = (1 -3/4)A + 3/4B = (A +3B)/4
Using the given point coordinates, we have ...
P = ((-4, -2) +3(4, 10))/4 = (-4 +12, -2 +30)/4 = (8, 28)/4
P = (2, 7)
