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serg [7]
3 years ago
5

Decrease the quantity as required(a) 100 by 25%​

Mathematics
1 answer:
Allisa [31]3 years ago
5 0

Answer:

75

Step-by-step explanation:

100% --- 100

100% - 25% --- ?

75% --- \frac{75}{100} × 100 = 75

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A water tank is box shaped with a square base of side length 5 ft. The tank is fed by a pipe above and drains from its base. In
adell [148]

Answer:

dy/dt = - (1/5) ft/s = - 0.2 ft/s

Step-by-step explanation:

Given

L = 5 ft

Qin = 25 ft³/s

Qout = 30 ft³/s

h = 10 ft

dy/dt = ?

We can apply the relation

ΔQ = Qint - Qout = 25 ft³/s - 30 ft³/s

⇒ ΔQ = - 5 ft³/s

Then we use the formula

Q = v*A

where Q = ΔQ, A = L²  is the area of square base and v = dy/dt  is the rate of change in the depth of the solution in the tank

⇒ ΔQ = (dy/dt)*L²

⇒ dy/dt = ΔQ/L²

⇒ dy/dt = (- 5 ft³/s)/(5 ft)²

⇒ dy/dt = - (1/5) ft/s = - 0.2 ft/s

6 0
3 years ago
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Law Incorporation [45]
.....................7 x 5 = 35
5 0
3 years ago
Read 2 more answers
Find a fraction or mixed number equivalent to each decimal.
Sphinxa [80]

Answer:

13. 1/3

14. 1/20

15. 9/20

16. 9/200

17. 253/25

18. 39/10

7 0
3 years ago
Cubed root x cubed root x2​
Yuki888 [10]

Answer:

Final answer is \sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x.

Step-by-step explanation:

Given problem is \sqrt[3]{x}\cdot\sqrt[3]{x^2}.

Now we need to simplify this problem.

\sqrt[3]{x}\cdot\sqrt[3]{x^2}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}

Apply formula

\sqrt[n]{x^p}\cdot\sqrt[n]{x^q}=\sqrt[n]{x^{p+q}}

so we get:

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{1+2}}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{3}}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x

Hence final answer is \sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x.

7 0
3 years ago
Solve the system by graphing. It is REQUIRED to check your solution. Show work for this problem on your work page.
Hunter-Best [27]

Answer:

y=x-1

y=-2x-4

although I cant summon a graph for this one, I can give cords

for first graph (-2,-3),(-1,-2),(0,-1), (1,0),(2,1)

For second graph the slope is down 2 over 1, and begins at (0,-4).

(-2,0)(-1,-2),(0,-4),(1,-6),(2,-8)

6 0
3 years ago
Read 2 more answers
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