Answer:
I believe the correct is A) The data is not symmetrical, so the mean is the best measure of center for the data.
Step-by-step explanation:
I am not 100% sure this is correct, if its wrong, im so sorry
1. statement- quadrilateral ABCD Reason- diagonal AEC
Answer:
1/3 or 0.3 (recurring)
Step-by-step explanation:
Let's substitute our numbers into the equation.
27 = 9x + 24 I multipled 8 by 3 in order to get 24, because x equals 3.
Now take away 24 leaving 9x on its own.
3 = 9x
Divide 9 to separate it from x.
3/9 = x
Simplify the fraction.
1/3 = x
Answer:
Step-by-step explanation:
Question 1
System of equations is,
y = -6x -------(1)
y = -4x - 2 ---------(2)
Substitute the value of y from equation (1) to equation (2)
-6x = -4x - 2
-6x + 4x = -2
-2x = -2
x = 1
From equation (1)
y = -6(1)
y = -6
Question (2)
System of equations is,
-y = x --------(1)
3x + 5y = 20 ---------(2)
Substitute the value of x from equation (1) to equation (2)
3(-y) + 5y = 20
-3y + 5y = 20
2y = 20
y = 10
From equation (1)
-y = x
x = -10
Question (3)
System of the equations is,
y = -2x - 7 --------(1)
9x - 10y = 12 ----------(2)
Substitute the value of y from equation (1) to equation (2)
9x - 10(-2x - 7) = 12
9x + 20x + 70 = 12
29x = 12 - 70
29x = -58
x = -2
From equation (1)
y = -2(-2) - 7
y = 4 - 7
y = -3
Answer:
Step-by-step explanation:
The null hypothesis is
H0: μ = 32.6
The alternative hypothesis is
Ha: μ ≠ 32.6
The calculated test statistic is 2.66 for the right tail and - 2.66 for the left tail
Since the critical values for both tails is ± 2.145, we would compare the critical values with the test statistic values
In order to reject the null hypothesis, the test statistic must be smaller than - 2.145 or greater than 2.145
Since - 2.66 < - 2.145 and 2.66 > 2.145, we would reject the null hypothesis.
Therefore, Reject H0. There is sufficient evidence to support the claim that the mean is different from 32.6.
2) Test statistic: t = 2.66. Critical values: t = ±1.96
Since - 2.66 < - 1.96 and 2.66 > 1.96, we would reject the null hypothesis. Then
Reject H0. There is sufficient evidence to support the claim that the mean is different from 32.6.