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3 years ago

PLZ ANSWER IF U KNOW THE ANSWER

Mathematics

2 answers:

creativ13 [48]3 years ago

3 0

Answer: its b

Step-by-step explanation:

stiv31 [10]3 years ago

3 0

Answer:

Step-by-step explanation:

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Please help i’ll give brainliest if correct

Naily [24]

The median is 44 (the center line)

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2 years ago

Read 2 more answers

5sin²α+3cos²α / 3sin²α-5cos²α = <br> if tgα=√2

fiasKO [112]

Tgα = tan(α) = sqrt(2)/1 = opposite/ adjacent
opposite = sqrt(2)
adjacent = 1
hypotenuse = sqrt(opposite^2 + adjacent^2)
= sqrt(sqrt(2)^2 + 1^2) = sqrt(3)

sin(α) = opposite/hypotenuse
= sqrt(2)/sqrt(3)

cos(α) = adjacent/hypotenuse
= 1/sqrt(3)

now we can calculate the value of
5sin²α+3cos²α / 3sin²α-5cos²α
... do the math

8 0

3 years ago

A card is randomly selected from a standard

Anni [7]

Answer:

5.8% or 6%

Step-by-step explanation:

6 face cards in a deck minus the red ones so it would be [6-3=3]

52 cards are in a deck and you have 3 black face card so it would be [3/52=0.0576]

Then to get your percentage it would be [0.0576 x 100=5.76%]

5.76 rounded up is 6%

6 0

3 years ago

Consider the function f(x) = 3x − 2. Select True or False for each statement. The y-intercept is 2. A True B False The x-interce

iragen [17]

Answer: A false, B true, C true

Step-by-step explanation:

A) intercept with y axis

That means x=0

y= 3*0-2

y= -2 So A is false

B) intercept with x axis

That means y=0

0= 3x-2

2=3x

2/3= x B is true

C) The form of linear function is

f(x)= mx +n, where m is the slope

In this case m= 3 so C is true

8 0

3 years ago

mr.browns salary is 32,000 and imcreases by $300 each year, write a sequence showing the salary for the first five years when wi

chubhunter [2.5K]

Hello!

We have the following data:

a1 (first term or first year salary) = 32000

r (ratio or annual increase) = 300

n (number of terms or each year worked)

We apply the data in the Formula of the General Term of an Arithmetic Progression, to find in sequence the salary increases until it exceeds 34700, let us see:

formula:

$a_n = a_1 + (n-1)*r$

* second year salary

$a_2 = a_1 + (2-1)*300$

$a_2 = 32000 + 1*300$

$a_2 = 32000 + 300$

$\boxed{a_2 = 32300}$

* third year salary

$a_3 = a_1 + (3-1)*300$

$a_3 = 32000 + 2*300$

$a_3 = 32000 + 600$

$\boxed{a_3 = 32600}$

* fourth year salary

$a_4 = a_1 + (4-1)*300$

$a_4 = 32000 + 3*300$

$a_4 = 32000 + 900$

$\boxed{a_4 = 32900}$

* fifth year salary

$a_5 = a_1 + (5-1)*300$

$a_5 = 32000 + 4*300$

$a_5 = 32000 + 1200$

$\boxed{a_5 = 33200}$

We note that after the first five years, Mr. Browns' salary has not yet surpassed 34700, let's see when he will exceed the value:

* sixth year salary

$a_6 = a_1 + (6-1)*300$

$a_6 = 32000 + 5*300$

$a_6 = 32000 + 1500$

$\boxed{a_6 = 33500}$

* seventh year salary

$a_7 = a_1 + (7-1)*300$

$a_7 = 32000 + 6*300$

$a_7 = 32000 + 1800$

$\boxed{a_7 = 33800}$

* eighth year salary

$a_8 = a_1 + (8-1)*300$

$a_8 = 32000 + 7*300$

$a_8 = 32000 + 2100$

$\boxed{a_8 = 34100}$

* ninth year salary

$a_9 = a_1 + (9-1)*300$

$a_9 = 32000 + 8*300$

$a_9 = 32000 + 2400$

$\boxed{a_9 = 34400}$

* tenth year salary

$a_{10} = a_1 + (10-1)*300$

$a_{10} = 32000 + 9*300$

$a_{10} = 32000 + 2700$

$\boxed{a_{10} = 34700}$

we note that in the tenth year of salary the value equals but has not yet exceeded the stipulated value, only in the eleventh year will such value be surpassed, let us see:

* eleventh year salary

$a_{11} = a_1 + (11-1)*300$