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const2013 [10]
3 years ago
13

The _____shows you how many molecules are present in the reaction.​

Chemistry
1 answer:
kotegsom [21]3 years ago
4 0

Answer:

number of atoms

i think sorry if this isnt right x

Explanation:

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A non polar solute will most likely dissolve in a polar solvent because opposites attract. Select one: True False
Klio2033 [76]

false because like dissolves like

non polar will dissolve non polar

polar will dissolve polar

7 0
3 years ago
What causes the different colors of layers in a sedimentary rock? A. the cooling process of the magma B. the weather in the area
OLga [1]

Different colors of sedimentary rock are determined by the environment where they are located. For example, red rocks form where oxygen is present. Darker sediments form when the environment is oxygen poor.

So, basically, the weather and surroundings of the rock, so B.

4 0
3 years ago
Complete and balance the equation for this single-displacement reaction. Phases are optional. Li+NaOH-->
sdas [7]
The complete and <span>balanced equation for this single-displacement reaction would be written as follows:

</span><span>Li+NaOH--> LiOH + Na

In this reaction, lithium replace sodium in the compound sodium hydroxide forming lithium hydroxide and sodium metal as products. Hope this answers the question.</span>
6 0
4 years ago
Read 2 more answers
Suppose two chemicals are reacted together. It takes 1000 kJ of energy to break the bonds of the reactants and 850 kJ of energy
Deffense [45]
The true statement is :
B.The reaction will need an external energy source to proceed. It requires 150kJ more for it to take place. The difference between the energy consumed and the energy produced is 150kJ.
4 0
4 years ago
Read 2 more answers
A galvanic cell at a temperature of 25.0°C is powered by the following redox reaction:
Vlada [557]

<u>Answer:</u> The cell voltage of the given chemical reaction is 2.74 V

<u>Explanation:</u>

For the given chemical reaction:

Sn^{2+}(aq.)+Ba(s)\rightarrow Ba^{2+}(aq.)+Sn(s)

Here, gold is getting reduced because it is gaining electrons and nickel is getting oxidized because it is loosing electrons.

<u>Oxidation half reaction:</u>  Ba(s)\rightarrow Ba^{2+}(aq.)+2e^-;E^o_{Ba^{2+}/Ba}=-2.90V

<u>Reduction half reaction:</u>  Sn^{2+}(aq.)+2e^-\rightarrow Sn(s);E^o_{Sn^{2+}/Sn}=-0.14V

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

E^o_{cell}=-0.14-(-2.90)=2.76V

To calculate the EMF of the cell, we use the Nernst equation, which is:

E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Sn^{2+}]}{[Ba^{2+}]}

where,

E_{cell} = electrode potential of the cell = ?V

E^o_{cell} = standard electrode potential of the cell = +2.76 V

n = number of electrons exchanged = 2

[Ba^{2+}]=5.15M

[Sn^{2+}]=1.59M

Putting values in above equation, we get:

E_{cell}=2.76-\frac{0.059}{2}\times \log(\frac{1.59}{5.15})\\\\E_{cell}=2.74V

Hence, the cell voltage of the given chemical reaction is 2.74 V

8 0
4 years ago
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