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umka21 [38]
3 years ago
13

PLEASE ANSWERRRRRRRRRRR

Chemistry
1 answer:
andrew11 [14]3 years ago
5 0

Answer:

B if I remember right.

Explanation:

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What is an experimental control
attashe74 [19]

The experimental control is the standard used as a comparison for the experimental groups.


For example, you may be trying to find out how different types of disinfectants affect bacterial growth.  The control group would receive <em>no</em> disinfectant whereas the experimental groups would be the ones on which the disinfectants were tested.


Hope this makes sense!

3 0
4 years ago
How many moles of H2SO4 are present in 0.500 L of a 0.150 M H2SO4 solution?
bonufazy [111]

Answer: 0.075

Explanation:

(concentration in molarity)(volume in liter) = answer

0.15 mol/L *0.500L = 0.075 mol

3 0
3 years ago
The heat of fusion AH, of ethyl acetate (C4H802) is 10.5 kinol. Calculate the change in entropy as when 398. g of ethy, acetate
Hitman42 [59]

<u>Answer:</u> The entropy change of the ethyl acetate is 133. J/K

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of ethyl acetate = 398 g

Molar mass of ethyl acetate = 88.11 g/mol

Putting values in above equation, we get:

\text{Moles of ethyl acetate}=\frac{398g}{88.11g/mol}=4.52mol

To calculate the entropy change for different phase at same temperature, we use the equation:

\Delta S=n\times \frac{\Delta H_{fusion}}{T}

where,  

\Delta S = Entropy change  = ?

n = moles of ethyl acetate = 4.52 moles

\Delta H_{fusion} = enthalpy of fusion = 10.5 kJ/mol = 10500 J/mol   (Conversion factor:  1 kJ = 1000 J)

T = temperature of the system = 84.0^oC=[84+273]K=357K

Putting values in above equation, we get:

\Delta S=\frac{4.52mol\times 10500J/mol}{357K}\\\\\Delta S=132.9J/K

Hence, the entropy change of the ethyl acetate is 133. J/K

7 0
3 years ago
How many moles are in 3.4 x 10^23 atoms of O2?
Tamiku [17]

Answer:

5.00 moles..hope it helps

7 0
3 years ago
How many grams of water at 25 C must be mixed in an insulated container with 250 grams of water at 93 C if the final temperature
nydimaria [60]

Answer:

Explanation

Comment

Normally you would just use m*c*delta T. But the c is the same in both cases, so you need just use m*deltaT

Givens

25 degrees

m = ?

T = 25

t = final temp = 75

93 degrees

m = 250

T = 93

t = final temp = 75

Solution

(t - 25)*m = (93 - t) * 250                   Remove the brackets

75*m - 25m = 93*250 -  250*75      Combine the right

m(75 - 25) = 23250 - 250*75

50 m = 23250 - 18750                      Combine

50 m = 4500                                      Divide both sides by 50

50*m/50 = 4500/50

m = 90

Answer: 90 grams are needed.

7 0
2 years ago
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