Use the poin-slope form of the equation of a line:-
y - y1 = m(x - x1) (where m = slope and the point is (x1, y1))
Plugging in the given values:-
y - 6 = 2/5(x - 10)
multiplying through by 5:-
5y - 30 = 2(x - 10)
5y - 30 = 2x - 20
5y = 2x + 10
In standard form the equation is
2x - 5y = -10 (answer)
Answer:
The objective function in terms of one number, x is
S(x) = 4x + (12/x)
The values of x and y that minimum the sum are √3 and 4√3 respectively.
Step-by-step explanation:
Two positive numbers, x and y
x × y = 12
xy = 12
S(x,y) = 4x + y
We plan to minimize the sum subject to the constraint (xy = 12)
We can make y the subject of formula in the constraint equation
y = (12/x)
Substituting into the objective function,
S(x,y) = 4x + y
S(x) = 4x + (12/x)
We can then find the minimum.
At minimum point, (dS/dx) = 0 and (d²S/dx²) > 0
(dS/dx) = 4 - (12/x²) = 0
4 - (12/x²) = 0
(12/x²) = 4
4x² = 12
x = √3
y = 12/√3 = 4√3
To just check if this point is truly a minimum
(d²S/dx²) = (24/x³) = (8/√3) > 0 (minimum point)
Answer:
Expression that can be written in the box on the other side of the equation will be x
Step-by-step explanation:
The left side of equation is:
Simplifying the equation we get:
An equation has no solution when, we cannot find the value of x.
So, The order side of equation can be x
i.e,
So, expression that can be written in the box on the other side of the equation will be x
The solution for this problem is:
The population is 500 times bigger since 8000/24 = 500. The population after t days is computed by:P(t) = P₀·4^(t/49)
Solve for t: 8000 = 8·4^(t/49) 1000 = 4^(t/49) log₄(1000) = t/49t = 49log₄(1000) ≅ 244 days
Unfortunately, Tashara, you have not provided enuf info from which to calculate the values of a and b. If you were to set <span>F(x)=x(x+a)(x-b) = to 0, then:
x=0,
x=-a
x=-b
but this doesn't answer your question.
Double check that you have shared all aspects of this question.</span>
