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3 years ago

2³- (3x5²) PLEASE HELP 20 POINTS , also show ur work, thank u sm!

Mathematics

2 answers:

Mumz [18]3 years ago

8 0

Answer:

Step-by-step explanation:

Alexxx [7]3 years ago

3 0

Answer:

-67

Step-by-step explanation:

2^3-(3*5^2)

simplify exponents

8-3*25

8-75

=-67

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The scale drawing represents an existing barn. The shortest side of the barn measures 150 meters. If a new barn that is 2/3 its

Snezhnost [94]

Answer:

1:1.5

Step-by-step explanation:

We have that 150 meters in the reality and the new size in the drawing is 2/3, therefore

150mtrs(old) * 2/3 = 100mtrs(new), also 100 mtrs. in the drawing are 150mtrs. in the reality or 1 is to 1.5

1:1.5

5 0

3 years ago

A genetic experiment involving peas yielded one sample of offspring consisting of 430 green peas and 155 yellow peas. Use a 0.05

Dimas [21]

Answer:

the null and alternative hypothesis are

$H_{0}$ : p=0.24

$H_{a}$ : p≠0.24

Test statistic is 1.416.

P-Value is 0.1568

We fail to reject the null hypothesis under 0.05 significance level

<em>At 0.05 significance</em> we cannot say that the proportion of offspring peas will be yellow is not 0.24 (24%)

Step-by-step explanation:

Let p be the proportion of offspring peas will be yellow. Then,

$H_{0}$ : p=0.24

$H_{a}$ : p≠0.24

test statistic can be calculated as

z= $\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } }$ where

p(s) is the sample proportion of yellow offspring peas ( $\frac{155}{155+430} =0.265$
p is the proportion of yellow offspring peas assumed under null hypothesis. (0.24)

N is the sample size (585)

Test statistic is z= $\frac{0.265-0.24}{\sqrt{\frac{0.24*0.76}{585} } }$ ≈ 1.416.

Using z-table, we can find that P-Value is 0.1568

We fail to reject the null hypothesis under 0.05 significance level since 0.157>0.05

We can conclude that <em>at 0.05 significance</em> we cannot say that the proportion of offspring peas will be yellow is not 0.24 (24%)

6 0

3 years ago

How can I complete this assignment.

Mademuasel [1]

Answer:

what assignment.

Step-by-step explanation:

5 0

2 years ago

You have just completed an experiment measuring the length (in mm) of 12 soybean plants after 3 days of sprouting. The measureme

sweet-ann [11.9K]

Answer:

The new IQR is 22.

Step-by-step explanation:

We are given the following data of length (in mm) of 12 soybean plants after 3 days of sprouting.

53, 47, 51, 54, 43, 39, 61, 57, 55, 46, 44, 43

Sorted data:

39, 43, 43, 44, 46, 47, 51, 53, 54, 55, 57, 61

Formula:

$IQR = Q_3 - Q_1\\Q_3 = \text{upper median},\\Q_1 = \text{ lower median}$

$Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}$

$Median ==\dfrac{6^{th}+7^{th}}{2} \dfrac{47+51}{2} = 49$

$Q_1 =\dfrac{3^{rd}+4^{th}}{2} = \dfrac{43 + 44}{2} = 43.5\\\\Q_3 =\dfrac{9^{th}+10^{th}}{2}= \frac{54 + 55}{2} = 54.5$

IQR = $Q_3 -Q_1 =54.5-43.5= 11$

If every measurement is doubled, then, the IQR will also double itself.

Thus,

New IQR =

$2\times \text{IQR}\\=2\TIMES 11\\=22$

Thus, the new IQR is 22.

4 0

3 years ago

Determine what type of model best fits the given situation: Farmer Joe has 1,000 bushels of corn to sell. Presently the market p

3241004551 [841]

Answer:

C. Quadratic model

Step-by-step explanation:

Determine what type of model best fits the given situation: Farmer Joe has 1,000 bushels of corn to sell. Presently the market price for corn is $5.00 a bushel. He expects the market price to increase by $0.15 per week. For each week he waits to sell, he loses ten bushels due to spoilage. A. none of these B. exponential C. quadratic D. linear

Given:

The quantity of corn Farmer Joe has to sell = 1,000 bushels

The present market price for corn = $5.00 a bushel

The amount by which he expects the market price to rise per week =$0.15

The number of bushels lost to spoilage per week = 10

The price of the corn per bushel with time = 5 + 0.15×t

The amount of corn left with time= 1000 - 10×t

Where;

t = Time in minutes

Value of the corn = Amount of corn left × Price of corn

Value of the corn = (1000 - 10×t) × (5 + 0.15×t)

=(1000-10t) × (5+0.15t)

=5,000 + 150t - 50t - 1.5t²

= -1.5t² +100t + 5000

Value of the corn= -1.5t² +100t + 5000.

It is a quadratic model

4 0

3 years ago