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larisa [96]
3 years ago
6

How can I complete this assignment.

Mathematics
1 answer:
Mademuasel [1]3 years ago
5 0

Answer:

what   assignment.

Step-by-step explanation:

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50% of all the cakes jenny baked were party cakes, 1/5 were fruit cakes and the remainder were sponge cakes. What percentage of
anygoal [31]
So basically you want to find the total percentage of cakes that weren't sponge cakes first.

You already have the 50% of party cakes. For the 1/5 percent of fruit cakes, you can multiply it by 20/20, to get 20/100, and then just take the 20 to get 20% that were fruit cakes.

Now you can just add the percentages together.

50% + 20% = 70%

So now you know 70% weren't sponge cakes, out of 100%.

So here you can just subtract 70% from 100% to figure out the remaining part of 100%, which must be sponge cakes.

100% - 70% = 30%

So 30% of the cakes were sponge cakes.
6 0
3 years ago
How to find the area of a capital 'L' shaped shape?
DENIUS [597]
You split the L into 2 parts, solve the area of the 2 parts, then add the areas together.
8 0
3 years ago
Find the absolute minimum and absolute maximum values of f on the given interval. f(t) = t 25 − t2 , [−1, 5]
Zina [86]

Answer: Absolute minimum: f(-1) = -2\sqrt{6}

              Absolute maximum: f(\sqrt{12.5}) = 12.5

Step-by-step explanation: To determine minimum and maximum values in a function, take the first derivative of it and then calculate the points this new function equals 0:

f(t) = t\sqrt{25-t^{2}}

f'(t) = 1.\sqrt{25-t^{2}}+\frac{t}{2}.(25-t^{2})^{-1/2}(-2t)

f'(t) = \sqrt{25-t^{2}} -\frac{t^{2}}{\sqrt{25-t^{2}} }

f'(t) = \frac{25-2t^{2}}{\sqrt{25-t^{2}} } = 0

For this function to be zero, only denominator must be zero:

25-2t^{2} = 0

t = ±\sqrt{2.5}

\sqrt{25-t^{2}} ≠ 0

t = ± 5

Now, evaluate critical points in the given interval.

t = -\sqrt{2.5} and t = - 5 don't exist in the given interval, so their f(x) don't count.

f(t) = t\sqrt{25-t^{2}}

f(-1) = -1\sqrt{25-(-1)^{2}}

f(-1) = -\sqrt{24}

f(-1) = -2\sqrt{6}

f(\sqrt{12.5}) = \sqrt{12.5} \sqrt{25-(\sqrt{12.5} )^{2}}

f(\sqrt{12.5}) = 12.5

f(5) = 5\sqrt{25-5^{2}}

f(5) = 0

Therefore, absolute maximum is f(\sqrt{12.5}) = 12.5 and absolute minimum is

f(-1) = -2\sqrt{6}.

8 0
3 years ago
The temperature changed from -1 degrees to +10 degrees. How much did the temperature change
Anvisha [2.4K]

Answer:

yes it is +11

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Minnie has 4 different stamps. She needs 3 to mail a large letter. How many ways can she pick the 3 that will be used?
timurjin [86]
Number of ways of picking a smaller number out of a bigger number is called combination.
Number of way of picking 3 stamps out of 4 is 4C3 (4 combination 3) = 4! / (3! x (4 - 3)!) = 4! / (3! x 1!) = (4 x 3 x 2 x 1) / (3 x 2 x 1 x 1) = 24 / 6 = 4 ways.
7 0
3 years ago
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