Answer:
I think its y^-3
Step-by-step explanation:
Since y^-3/y^-2 are both negatives they would swap places to become positive - y^2/y^3
then using rules of exponents you would subtract the exponents witch would be y^-3
Answer: C . 147π / 4 mi²
Concept:
The sector is the part of a circle is enclosed by two radii of a circle and their intercepted arc.
A = (θ / 360) πr²
θ = angle of the sector
π = constant
r = radius
Solve:
<u>Given variable</u>
θ = 270°
r = 7 mi
<u>Given formula</u>
A = (θ / 360) πr²
<u>Substitute values into the formula</u>
A = (270 / 360) π (7)²
<u>Simplify exponents</u>
A = (270 / 360) π 49
<u>Simplify by multiplication</u>
A = (147 / 4) π
A = 147π / 4
Hope this helps!! :)
Please let me know if you have any questions
Answer:
which class question is this
Answer:
See below
Step-by-step explanation:
Your question is a bit unclear, so I'm going to assume you want the value of y or x:
(y+3)^2=-12(x-2)
-(y+3)^2/12=x-2
-(y+3)^2/12+2=x
(y+3)^2=-12(x-2)
y+3=sqrt(-12x+24)
y=sqrt(-12x+24)-3
Answer:
Step-by-step explanation:
add 12 and a number: 12 + c
subtract a number from 12: 12 - c
divide a number by 12: c : 12 or c/12
multiply 12 by a number: 12 · c = 12c
