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3 years ago

Can someone please help me cause i am so confused

Mathematics

1 answer:

strojnjashka [21]3 years ago

3 0

Answer:

Ya dig?

Step-by-step explanation: You gon choose me baby.

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What it 55/100 in simplest form

den301095 [7]

55/100 = (55:5)/(100:5) = 11/20

55/100 = 0.55

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3 years ago

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Kende also bought a bookmark. The combined amount he paid for the books and the

mrs_skeptik [129]

Answer:

10$

Step-by-step explanation:

Trust me :)

7 0

3 years ago

Please help 15 POINTS PROBLEM BELOW

Anit [1.1K]

be sure to use PEMDAS so first use the distributive property then work your way from there.

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I need help with 5-6 PLEASEEEE!! Also please excuse the answers cause I know it’s wrong

sergey [27]

Step-by-step explanation:

angle STQ is the supplementary angle (together they are 180° below line MQ) to 2x + 8.

above ST we have a group of 3 angles that combine to 180° :

2x + 8

90°

71 - x

so, to get x first :

2x + 8 + 90 + 71 - x = 180

x + 169 = 180

x = 11

so, the angle MTS =

2x + 8 = 2×11 + 8 = 22 + 8 = 30°.

therefore, the angle STQ is

180 - angle MTS = 180 - 30 = 150°.

7 0

2 years ago

A farmer wants to fence a rectangular garden next to his house which forms the northern boundary. The fencingfor the southern bo

Ivahew [28]

Answer:

10 ft x 10 ft

Area = 100 ft^2

Step-by-step explanation:

Let 'S' be the length of the southern boundary fence and 'W' the length of the eastern and western sides of the fence.

The total area is given by:

$A=S*W$

The cost function is given by:

$\$ 120 = \$3*2W+\$6*S\\20 = W+S\\W = 20-S$

Replacing that relationship into the Area function and finding its derivate, we can find the value of 'S' for which the area is maximized when the derivate equals zero:

$A=S*(20-S)\\A=20S-S^2\\\frac{dA}{dS} = \frac{d(20S-S^2)}{dS}\\0= 20-2S\\S=10$

If S=10 then W =20 -10 = 10

Therefore, the largest area enclosed by the fence is:

$A=S*W\\A=10*10 = 100\ ft^2$

5 0

3 years ago