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irina [24]
2 years ago
12

How do I find the value of e any help please​

Mathematics
1 answer:
anygoal [31]2 years ago
4 0

Answer:

97

Step-by-step explanation:

360-117-146 is 97

Gimmi brainest answer :)

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kwasi thought of a number, multiplied it by7/2 and added 16 to the results.if the final answer was 30.what number did he think o
ziro4ka [17]

Answer:

4

Step-by-step explanation:

  1. represent the number he thought of with x

\frac{7}{2} x + 16 = 30

  1. multiply through with the LCM which is 2
  2. 2 \times  \frac{7}{2}x + 16 \times 2 = 30 \times 2
  3. 7x + 32 = 60
  4. 7x = 60 - 32
  5. 7x = 28
  6. \frac{7x}{7}  =  \frac{28}{7}
  7. x = 4
7 0
2 years ago
PLEASE ANSWER<br><br> what does ok mean?
tia_tia [17]

I use it as a short way to say "okay" but I don't know how others may use it.

6 0
3 years ago
Factor each expression 8 16 =
dalvyx [7]
Since they are just next to each other ill take it multiplication and that would be 128 if its not let me know and ill correct it 
8 0
3 years ago
A bouncing rubber ball has each of the following except _____.
REY [17]
The answer is c heat
6 0
3 years ago
In a large population, 3% of the people are heroin users. A new drug test correctly identifies users 93% of the time and correct
kari74 [83]

Answer:

(a) The probability tree is shown below.

(b) The probability that a person who does not use heroin in this population tests positive is 0.10.

(c) The probability that a randomly chosen person from this population is a heroin user and tests positive is 0.0279.

(d) The probability that a randomly chosen person from this population tests positive is 0.1249.

(e) The probability that a person is heroin user given that he/she was tested positive is 0.2234.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is a heroin user

<em>Y</em> = the test is correct.

Given:

P (X) = 0.03

P (Y|X) = 0.93

P (Y|X') = 0.99

(a)

The probability tree is shown below.

(b)

Compute the probability that a person who does not use heroin in this population tests positive as follows:

The event is denoted as (Y' | X').

Consider the tree diagram.

The value of P (Y' | X') is 0.10.

Thus, the probability that a person who does not use heroin in this population tests positive is 0.10.

(c)

Compute the probability that a randomly chosen person from this population is a heroin user and tests positive as follows:

P(X\cap Y)=P(Y|X)P(X)=0.93\times0.03=0.0279

Thus, the probability that a randomly chosen person from this population is a heroin user and tests positive is 0.0279.

(d)

Compute the probability that a randomly chosen person from this population tests positive as follows:

P (Positive) = P (Y|X)P(X) + P (Y'|X')P(X')

                  =(0.93\times0.03)+(0.10\times0.97)\\=0.1249

Thus, the probability that a randomly chosen person from this population tests positive is 0.1249.

(e)

Compute the probability that a person is heroin user given that he/she was tested positive as follows:

P(X|positive)=\frac{P(Y|X)P(X)}{P(positive)} =\frac{0.93\times0.03}{0.1249}= 0.2234

Thus, the probability that a person is heroin user given that he/she was tested positive is 0.2234.

6 0
3 years ago
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