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ira [324]
3 years ago
7

Find the median and mean of the data set below: 6 , 37 , 2 , 38 , 1 , 3 , 46 6,37,2,38,1,3,46

Mathematics
1 answer:
IgorLugansk [536]3 years ago
8 0

Answer:

Mean: 19

Median: 6

Step-by-step explanation:

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Can someone assist me with these Algreba questions olease?
Delicious77 [7]

the answer have to be would be (-3, 1)

4 0
3 years ago
Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that
kherson [118]

Answer:

The answer is

f(x) = {\displaystyle  8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }

Step-by-step explanation:

Remember that Taylor says that

f(x) = {\displaystyle \sum\limits_{k=0}^{\infty} \frac{f^{(k)}(a) }{k!}(x-a)^k }

For this case

f^{(0)} (-2) = 8(-2)-3(-2)^3 = 8\\f^{(1)} (-2) = 8-3(3)(-2)^2 = -28\\f^{(2)} (-2) = -3(3)2(-2) = -36\\f^{(2)} (-2) = -3(3)2 = -18

f(x) = {\displaystyle  8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }

5 0
3 years ago
Am solving this problem correct
cestrela7 [59]
A) The degree of the first term is... 1
first \ term = 3t
The degree of the second term is... 2
second \ term = t^2
The degree of the third term is... 4
third \ term = t^4

b) The leading term of the polynomial is... 7t⁴
The leading coefficient of the polynomial is... 7

c) The degree of the polynomial is... 4
6 0
3 years ago
Read 2 more answers
Use K to write an equation, y=kx, for the relationship.
frozen [14]
Y= 1x because the slope is 1 because rise over run 1
8 0
2 years ago
Which functions could represent a reflection over the y axis of the given function
fredd [130]

Answer:

g(x) = 1/2*(4)^(–x)          and

g(x) =1/2*(1/4)^(x)

Please, see attached picture.

Step-by-step explanation:

Your full question is attached in the picture below

To easily solve this problem, we can graph each equation and see, which one represents a reflection of the function over the y axis.

See, second image.

The answers are

g(x) = 1/2*(4)^(–x)          and

g(x) =1/2*(1/4)^(x)

4 0
2 years ago
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