It’s a little complicated but here’s how it works:
Imagine a table with the intervals
0:4 , 4:6 , 6:7 , 7:10 , 10:13 (10 year intervals)
Then we have different rows
Class width: 4 , 2 , 1 , 3 , 3
Freq density: 0.2 , 0.5 , 1.2 , 0.7 , 0.3
So now calculate frequency where freq = class width * density
Freq: 0.8 , 1 , 3.6 , 2.1 , 0.9
So to find median find cumulative frequency
(Add all freq)
Cfreq = 8.4 now divide by 2 = 4.2
So find the interval where 4.2 lies.
0.8 + 1 = 1.8 + 3.6 = 5.6
So 4.2 (median) will lie in that interval 60-70 years.
Answer:
A. We have extremely strong evidence to reject H0.
Step-by-step explanation:
Let P be the proportion of non-retirees in 2015 who did not think that Social Security would be able to pay a retirement benefit by the time that they retire.
According to the data null and alternative hypotheses should be:
: P=0.60
: P<0.60
Test statistics is -4.29 and p-value of the statistics is p<0.001
At every significance levels higher than 0.001, we can reject the null hypothesis since p<0.001.
Answer:
13 bags
Step-by-step explanation:
Area of the lawn: A=lw
w= 64 ft
P= 2(l+w)= 278 ft ⇒
bags of seed required:
- 4800/384= 12.5 so 13 full bags needed
Answer:
w = 3 is your answer.
Step-by-step explanation:
You want to get w by itself.
<em>(2w - 1)/(4) = 2 - w </em><u>You will add the w on both sides.</u>
<em>(3w - 1)/(4) = 2 </em><u>You will multiply 4 on both sides.</u>
<em>3w - 1 = 8 </em><u>You will add 1 on both sides.</u>
<em>3w = 9 </em><u>You will divide 3 on both sides.</u>
w = 3 is your answer.
The mode for this set of numbers is 18 because there are three 18's in the set of number, and only two 20's. :D
