You're looking for the largest number <em>x</em> such that
<em>x</em> ≡ 1 (mod 451)
<em>x</em> ≡ 4 (mod 328)
<em>x</em> ≡ 1 (mod 673)
Recall that
<em>x</em> ≡ <em>a</em> (mod <em>m</em>)
<em>x</em> ≡ <em>b</em> (mod <em>n</em>)
is solvable only when <em>a</em> ≡ <em>b</em> (mod gcd(<em>m</em>, <em>n</em>)). But this is not the case here; with <em>m</em> = 451 and <em>n</em> = 328, we have gcd(<em>m</em>, <em>n</em>) = 41, and clearly
1 ≡ 4 (mod 41)
is not true.
So there is no such number.
Answer:
answer B: (2,-2)
Step-by-step explanation:
First, write the equations on top of each other:

Then, multiply the the second equation by 2 so that we can use elimination of the y-variable:

Next, use elimination to find the value of "x":

So, your x-value is 2.
Now, substitute your x-value into one of your equations, let's take the second equation, 2x-y=6:

Your y-value is -2.
With all your information gathered, you find that the solution to this system of equation is (2,-2).
Answer: If you divide 73 by one hundred you get 73 hundredths as a decimal which is 0.73.
Step-by-step explanation:
I’m also struggling with that but it’s the perimeter of a right triangle
Answer:
The answer is
<h2>

</h2>
Step-by-step explanation:
The midpoint M of two endpoints of a line segment can be found by using the formula
<h3>

</h3>
where
(x1 , y1) and (x2 , y2) are the points
From the question the points are
A(-4, 7) and S(5,3)
The midpoint is
<h3>

</h3>
We have the final answer as
<h3>

</h3>
Hope this helps you