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Furkat [3]
3 years ago
11

Please help! I’ll mark brainliest

Mathematics
1 answer:
Usimov [2.4K]3 years ago
8 0

Answer: 19 ≥ 3z + 1 ≥ - 5

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if a sum of money increased by 1/5 of itself every year and in 5 years amounts to Rs.8546,find the sum
weqwewe [10]

Answer:

Answer :

Given  : If a sum of money amounts to Rs 2200 in 5 years

Let sum of money =  x

And as given : The interest is 3838 of the principal . So we get

x ( 3838 ) = 2200 - x

3x  =  17600 - 8x

11x  =  17600

x   =  1600

So, Sum of money  =  Rs . 1600

Then interest =  2200 -  1600 =  Rs . 600

Let Rate of interest  = r  %

And we know Simple interest  = P × r × t100P × r × t100 , So we get

⇒1600 × r × 5100 =  600⇒16× r × 5100 =  6⇒80r  =  600⇒r = 60080 = 152 =  712%⇒1600 × r × 5100 =  600⇒16× r × 5100 =  6⇒80r  =  600⇒r = 60080 = 152 =  712%

So

Step-by-step explanation:

4 0
2 years ago
Diana invested $3000 in a savings account for 3 years
Vlad1618 [11]
What is the intrist rate ? kind of need that to answer 
5 0
3 years ago
Convert 88% to a decimal.<br> a .088<br> b .0088<br> c .88<br> d 8.8
Hitman42 [59]

Answer:

your answer will be c hope ur help and mark me brainlist

8 0
3 years ago
Read 2 more answers
Bonjour à tous, pouvez vous m'aider à trouver la réponse pour cette "question ouverte" svp?
AlekseyPX

La solution:

625 cm^2.

Explication étape par étape:

Si la forme est rectangulaire, elle aura la plus grande superficie possible quand la longueur équivaut à la largeur. Pour avoir un périmètre de 100 cm, cela signifie que chaque côté doit faire 25 cm.

La superficie serait alors de 25 cm x 25 cm = 625 cm^2.

8 0
2 years ago
First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x
e-lub [12.9K]

Answer:

(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

\int x ln(5+x)dx

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

\int (U-5) ln(U)dU

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

\int (pq')=pq-\int qp'

so we must define p, q, p' and q':

p=ln U

p'=\frac{1}{U}dU

q=\frac{U^{2}}{2}-5U

q'=U-5

and now we plug these into the formula:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU

Which simplifies to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU

Which solves to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C

so we can substitute U back, so we get:

\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C

and now we can simplify:

\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

notice how all the constants were combined into one big constant C.

7 0
3 years ago
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