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myrzilka [38]
3 years ago
6

Determine whether theses lines are parallel, perpendicular or neither

Mathematics
1 answer:
belka [17]3 years ago
8 0

Answer:

Lines 2 and 3 are parallel with slope (-2/3) and different y intercepts, and both are perpendicular to line 1              (-1) / (3/2) = (-2/3)

Step-by-step explanation:

Parallel lines have the same slope

Perpendicular lines have negative reciprocal slopes

line 1: 6x - 4y = 2

line 1: 4y =  6x - 2

line 1:   y = (3/2)x - 0.5

line 2:  y = (-2/3)x - 6

line 3:3y = -2x + 4

line 3: y = (-2/3)x + 4/3

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Step-by-step explanation:

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2 years ago
Help please i need it bad
evablogger [386]

Answer:

-13, -3

15, 2.6

Step-by-step explanation:

x, y are the numbers

x = 5y + 2

x×y = 39

(5y + 2)×y = 39

5y² + 2y - 39 = 0

the solution of a quadratic equation :

y = (-b ± sqrt(b² - 4ac))/2a

a = 5

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c = -39

y = (-2 ± sqrt(2² - 4×5×-39))/2×5 =

= (-2 ± sqrt(4 + 780))/10 =

= (-2 ± sqrt(784))/10 = (-2 ± 28)/10

y1 = (-2 + 28)/10 = 26/10 = 2.6

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5 0
2 years ago
3. Consider the sequence,-8, -5, -2, 1, ...
Naddik [55]

Answer:

a) a_n=3\,n-11

b) a_{20}=49

c) term number 17 is the one that gives a value of 40

Step-by-step explanation:

a)

The sequence seems to be arithmetic, and with common difference d = 3.

Notice that when you add 3 units to the first term (-80, you get :

-8 + 3 = -5

and then -5 + 3 = -2 which is the third term.

Then, we can use the general form for the nth term of an arithmetic sequence to find its simplified form:

a_n=a_1+(n-1)\,d

That in our case would give:

a_n=-8+(n-1)\,(3)\\a_n=-8+3\,n-3\\a_n=3n-11

b)

Therefore, the term number 20 can be calculated from it:

a_{20}=3\,(20)-11=60-11=49

c) in order to find which term renders 20, we use the general form we found in step a):

a_n=3\,n-11\\40=3\,n-11\\40+11=3\,n\\51=3\,n\\n=\frac{51}{3} =17

so term number 17 is the one that renders a value of 40

5 0
3 years ago
A number b increased by 3 is greater than or equal to -26
photoshop1234 [79]

A number b increased by 3 is greater than or equal to -26:

b+3\geq-26\qquad\text{subtract 3 from both sides}\\\\\boxed{b\geq-29}

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3 years ago
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