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insens350 [35]
3 years ago
5

ANSWER ASAP!!!!!!!!!!!!!!!!!!!!! Reflect (4, -4) over the x-axis. Then translate the result to the right 3 units. What are the c

oordinates of the final point? NO FILES PLEASE
Mathematics
1 answer:
cricket20 [7]3 years ago
4 0

Answer:

(7,4)

Step-by-step explanation:

The rule for reflecting over the x-axis is (x,y) -> (x,-y)

If you apply that to your point, you get (4,4)

When doing this translation, you add the 3 to the number you have in the x. This will give you (7,4).

Hope I helped.

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icang [17]
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AnnZ [28]

Answer:

3

Step-by-step explanation:

3 + 10= 13

13 x 3 = 39

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4 years ago
THIS IS 100 POINTS SOMEBODY PLEASEEEEEEEEEEEEEE HELP MEEEEE
Nookie1986 [14]

Answer: Option #4: the 0.2 could be changed to 2.

Explanation:

The table is designed to make the concept of percentages more understandable. The table first allocates the total amount of 70 in terms of its "fifths," or 20% parts. Then it expresses these parts in the last row of the table, showing that 20% of 70 is 14 and all the five parts sum up to 70 again.

Now, Mikel is supposed to express 40% of the amount. So she writes (incorrectly): 0.2 * 14. This statement needs to be changed to 2 * 14 (two times 14 = 28), to correspond to 2 times 20%, or 40%  of 70.

This is reflected in the last (fourth) option "The 0.2 in the expression could be changed to 2."

Option #3 is incorrect because changing 14 to 70, will result in an incorrect number (2.8).

Options 1 and 2 are similarly incorrect (as can be easily verified)

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4 years ago
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Nikolay [14]

When you have a negative exponent, you move the base with the negative exponent to the other side of the fraction to make the exponent positive.

For example:

\frac{1}{y^{-2}} =\frac{y^2}{1} or y^2

2x^{-3} or \frac{2^1x^{-3}}{1} =\frac{2}{x^3}

\frac{1}{x^{-5}} =x^5

When a base with an exponent is divided by a base with an exponent, you subtract the exponents together. (But you can only combine the exponents when the bases are the same)

For example:

\frac{x^2}{y}   (can't combine because they have different bases of y and x)

\frac{x^5}{x^3} =x^{(5-3)}=x^2

\frac{2^2}{2} =2^{(2-1)}=2^1 = 2

When you multiply an exponent directly to a base with an exponent, you multiply the exponents together.

For example:

(x^2)^3=x^{(2*3)}=x^6

(y^2)^{10}=y^{(2*10)}=y^{20}

\frac{2e^0}{(e^{-3})^2}     First multiply the exponents together in the denominator

\frac{2e^0}{e^{(-3*2)}}= \frac{2e^0}{e^{-6}}        Now subtract the exponents together

2e^{(0-(-6))}  (two negative signs cancel each other out and become positive)

2e^{(0+6)}

2e^6

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3 years ago
What is the Answer for this question
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The answer to this question is B
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