After a little manipulation, the given diff'l equation will look like this:
e^y * dy = (2x + 1) * dx.
x^2
Integrating both sides, we get e^y = 2------- + x + c, or e^y = x^2 + x + c
2
Now let x=0 and y = 1, o find c:
e^1 = 0^2 + 0 + c. So, c = e, and the solution is e^y = x^2 + x + e.
X=-53x+378, if you need explanation used ask me.
7/8=x/8
if x/y=z/y where y=y, then x=z
we have
7/8=x/8
8=8
therefor 7=x
the missing value=7
Look you math book up on sladder and it'll have all the answers for free!!!!!!!!!!!!!!!
Answer: Josh = 19.8 hours, Danny = 10.8 hours
<u>Step-by-step explanation:</u>


Since time cannot be negative, x=-5.8 is an extraneous solution (not valid) so x = 10.8
Josh: x + 9 --> 10.8 + 9 = 19.8
Danny: x --> 10.8
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2a) k = 9.45 & 0.55
2b) x = 3/2
2c) x = 2/3 <em>(x = -1 is an extraneous solution so is not valid)</em>
2d) No Solution <em>(x = 1 is an extraneous solution so is not valid)</em>
Here is the work for 2a. Follow this format for b, c, & d

