Please answer correctly !!!!!!!!!!!!!!!!!! Will mark brainliest !!!!!!!!!!!!!!!!!!
2 answers:
You might be interested in
Using the frequency table, it is found that:
a) 99.2% of the group of eggs were less than 24.75 mm long.
b) 0.471 = 47.1% probability that one of the eggs selected at random was at least 21.75 mm long but less than 24.75 mm long.
The frequency table gives the percentage of cuckoo bird eggs with the associated lengths.
- For example, 0.8% of eggs have lengths between 18.75 and 19.75 millimetres.
Item a:
- 0.8% of eggs were more than 24.75 mm.
Thus, 100 - 0.8 = 99.2% were less than 24.75 mm long.
Item b:
- 37.9% between 21.75 and 22.75 mm.
- 28.5% between 22.75 and 23.75 mm.
- 10.7% between 23.75 and 24.75 mm.
In total:
47.1% of the eggs are in these lengths, thus, 0.471 = 47.1% probability that one of the eggs selected at random was at least 21.75 mm long but less than 24.75 mm long.
A similar problem is given at brainly.com/question/24141790
Answer:
tiles
Step-by-step explanation:
there are many ways to solve this soo...
1. convert to centimetres (there are 100 centimetres in 1 metre)
2. the square tiles area =
2. find the large area (4.8m x 3.8m or 480cm x 380cm)
2. find the two smaller areas (1.2m x 1.8m or 120cm x 180cm)
3. add to find total area
4. find how many tiles are needed
tiles