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3 years ago

Please round this number to the second decimal: 113.097335529233

Mathematics

2 answers:

denpristay [2]3 years ago

8 0

Answer:

Step-by-step explanation:

The 7 in the hundreths place would bring the 9 up. So your answer would then be 113.10

beks73 [17]3 years ago

3 0

Answer:

113.1

Step-by-step explanation:

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Two cars leave from a town at the same time traveling in opposite directions. One travels 5 mph faster than the other. In 3 hour

Doss [256]

Let the slower cars speed equal X.

The faster cars speed would be X+5 ( 5 mph faster).

They traveled for 3 hours

Multiply the time of travel by speed to equal the number of miles traveled.

So you have:

3X + 3(X+5) = 267 miles

Simplify the left side:

3X + 3X+15 = 267

Combine like terms:

6x + 15 = 267

Subtract 15 from each side"

6x = 252

Divide each side by 6:

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3 years ago

Find the measure of x.<br> X<br> 55°<br> 80<br> X<br> = [ ?<br> ]<br> Round to the nearest tenth.

NARA [144]

<h3>Answer: 139.5</h3>

Work Shown:

cos(angle) = adjacent/hypotenuse

cos(55) = 80/x

x*cos(55) = 80

x = 80/cos(55)

x = 139.4757 approximately

x = 139.5

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PART A: Mrs. konsdorf claims that angle R is a right angle.Is Mrs. konsdorf correct? explain your reasoning PART B: if T is trab

Anna007 [38]

Answer:

Part A: Angle R is not a right angle.

Part B; Angle GRT' is a right angle.

Step-by-step explanation:

Part A:

From the given figure it is noticed that the vertices of the triangle are G(-6,5), R(-3,1) and T(2,6).

Slope formula

$m=\frac{y_2-y_1}{x_2-x_1}$

The product of slopes of two perpendicular lines is -1.

Slope of GR is

$\text{Slope of GR}=\frac{1-5}{-3-(-6)}=\frac{-4}{3}$

Slope of RT is

$\text{Slope of RT}=\frac{6-1}{2-(-3)}=\frac{5}{5}=1$

Product of slopes of GR and RT is

$\frac{-4}{3}\times 1=\frac{-4}{3}\neq -1$

Therefore lines GR and RT are not perpendicular to each other and angle R is not a right angle.

Part B:

If vertex T translated by rule

$(x,y)\rightarrow(x-1,y-2)$

Then the coordinates of T' are

$(2,6)\rightarrow(2-1,6-2)$

$(2,6)\rightarrow(1,4)$

Slope of RT' is

$\text{Slope of RT'}=\frac{4-1}{1-(-3)}=\frac{3}{4}$

Product of slopes of GR and RT' is

$\frac{-4}{3}\times \frac{3}{4}=-1$

Since the product of slopes is -1, therefore the lines GR and RT' are perpendicular to each other and angle GRT' is a right angle.

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