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Nataly_w [17]
2 years ago
14

HELP PLEASE HURRY... 65 POINTS

Mathematics
2 answers:
Katarina [22]2 years ago
6 0

Answer:

the answer is A

Step-by-step explanation:

your welcome sorry if im wrong

stepan [7]2 years ago
3 0
B is the answer to your question I remember putting that in my other class
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Did i do this right?
Sveta_85 [38]

Answer:

a) FALSE

Step-by-step explanation:

a) FALSE (it was translated from quadrant III to quadrant I)

b) TRUE

c) TRUE

d) TRUE

e) FALSE

8 0
3 years ago
28 1/2 divided by 4 3/4
lidiya [134]
228/28 1/2 ÷ 4 3/4 = 57/2 × 4/19= 228/38 = 6


Btw i did keep change flip
6 0
3 years ago
Read 2 more answers
Which of the following is a a solution to the equation y=3x-1
Burka [1]
For option a, y = 3(4) - 1 = 12 - 1 = 11                  [not correct]
For option b, y = 3(2) - 1 = 6 - 1 = 5                      [correct]

Therefore option b is a solution to the given equation.
6 0
3 years ago
Please help, thanks!
Mamont248 [21]
((-4x^3)(y^4))^-3
--------------------------
(2xy^4)^-4
16x^4y^16
=------------------------
-64x^9y^12
-16y^4
=------------------------
64x^5
-y
=------------------------
4x^5

So the final answer is:

-y^4
-------
4x^5

(Btw if "^" is in front of a number, that means it is an exponent, so when your writing this on paper, just write it as a regular exponent without the "^". I had to do that since I'm on a computer.)  

Hopefully this was helpful in some way. 

7 0
3 years ago
Part 1. Determine the molar mass of a 0.622-gram sample of gas having a volume of 2.4 L at 287 K and 0.850 atm. Show your work.
sdas [7]

If a sample of gas is a 0.622-gram, volume of 2.4 L at 287 K and 0.850 atm. Then the molar mass of the gas is 7.18.

<h3>What is an ideal gas equation?</h3>

The ideal gas equation is given below.

PV = nRT

The equation can be written as

\rm PV = \dfrac{m}{M} \ RT\\\\\\MPV = mRT

Where M is the molar mass, P is the pressure, V is the volume, R is the universal gas constant, T is the temperature, and m is the mass of the gas.

Then the molar mass of a 0.622-gram sample of gas has a volume of 2.4 L at 287 K and 0.850 atm.

V = 2.4 L = 0.0024

P = 0.85 atm = 86126.25 Pa

T = 287 K

m = 0.622

R = 8.314

Then we have

\begin{aligned} \rm M \times 86126.25 \times  0.0024&= 0.622 \times  8.314 \times 287\\\\\rm M &= 7.18 \end{aligned}

Then the molar mass of the gas is 7.18.

More about the ideal gas equation link is given below.

brainly.com/question/4147359

#SPJ1

6 0
1 year ago
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