the average adult breathes in about 37 L of air every 5 minutes. What is the rate of change of volume of air?

PLEASE HELP ASAP !!!! <br> Samantha says that (6^4)^-3 = 6. is she correct ? why or why not ?

Sphinxa [80]

Hey there! Let’s solve the question first.

(6^4)^-3= 4.593 or 4.6

The reason behind this, 6^4=1296^-3

And 1269^-3= 4.593 or 4.6

Hope this helps!

4 0

3 years ago

D) A certain production process takes two stages 1 and 2. In a given period 5,000 units were introduced in process one and the c

Flauer [41]

The cost per unit of the complete units assuming that defective units are sold at Ksh 20 per unit is Rm 93.73.

<h3>What is the cost per unit with defective units?</h3>

The cost per unit with defective units can be computed by subtracting the sales value of the sold defective units from the total production costs, thereby reducing the total production costs, and then dividing the resulting figure by the number of good units.

<h3>Data and Calculations:</h3>

Process 1 Process 2 Total costs

Materials Rm 100,000 150,000 250,000

Labor 50,000 50,000 100,000

Overheads 50,000 20,000 70,000

Total costs 420,000

Input units = 5,000

Output units = 4,480

Defective units = 520 (5,000 - 4,480)

Sales revenue from defective units = Rm 104 (520 x Rm 0.20)

Cost per unit = Rm 93.73 (Rm 420,000 - Rm 104)/4,480

Thus, the cost per unit of the complete units assuming that defective units are sold at Ksh 20 per unit is Rm 93.73.

Learn more about accounting for defective units at brainly.com/question/10035226

#SPJ1

3 0

2 years ago

Can u please help me pls i ll give 5 stars and a heart

Digiron [165]

Answer:

-3/5

Step-by-step explanation:

2/3 *-9/8*-4/5*-1= -3/5

8 0

2 years ago

Read 2 more answers

Problem 4: Let F = (2z + 2)k be the flow field. Answer the following to verify the divergence theorem: a) Use definition to find

Viktor [21]

Given that you mention the divergence theorem, and that part (b) is asking you to find the downward flux through the disk $x^2+y^2\le3$ , I think it's same to assume that the hemisphere referred to in part (a) is the upper half of the sphere $x^2+y^2+z^2=3$ .

a. Let $C$ denote the hemispherical <u>c</u>ap $z=\sqrt{3-x^2-y^2}$ , parameterized by

$\vec r(u,v)=\sqrt3\cos u\sin v\,\vec\imath+\sqrt3\sin u\sin v\,\vec\jmath+\sqrt3\cos v\,\vec k$

with $0\le u\le2\pi$ and $0\le v\le\frac\pi2$ . Take the normal vector to $C$ to be

$\vec r_v\times\vec r_u=3\cos u\sin^2v\,\vec\imath+3\sin u\sin^2v\,\vec\jmath+3\sin v\cos v\,\vec k$

Then the upward flux of $\vec F=(2z+2)\,\vec k$ through $C$ is

$\displaystyle\iint_C\vec F\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^{\pi/2}((2\sqrt3\cos v+2)\,\vec k)\cdot(\vec r_v\times\vec r_u)\,\mathrm dv\,\mathrm du$

$\displaystyle=3\int_0^{2\pi}\int_0^{\pi/2}\sin2v(\sqrt3\cos v+1)\,\mathrm dv\,\mathrm du$

$=\boxed{2(3+2\sqrt3)\pi}$

b. Let $D$ be the disk that closes off the hemisphere $C$ , parameterized by

$\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath$

with $0\le u\le\sqrt3$ and $0\le v\le2\pi$ . Take the normal to $D$ to be

$\vec s_v\times\vec s_u=-u\,\vec k$

Then the downward flux of $\vec F$ through $D$ is

$\displaystyle\int_0^{2\pi}\int_0^{\sqrt3}(2\,\vec k)\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv=-2\int_0^{2\pi}\int_0^{\sqrt3}u\,\mathrm du\,\mathrm dv$

$=\boxed{-6\pi}$

c. The net flux is then $\boxed{4\sqrt3\pi}$ .

d. By the divergence theorem, the flux of $\vec F$ across the closed hemisphere $H$ with boundary $C\cup D$ is equal to the integral of $\mathrm{div}\vec F$ over its interior:

$\displaystyle\iint_{C\cup D}\vec F\cdot\mathrm d\vec S=\iiint_H\mathrm{div}\vec F\,\mathrm dV$

We have

$\mathrm{div}\vec F=\dfrac{\partial(2z+2)}{\partial z}=2$

so the volume integral is

$2\displaystyle\iiint_H\mathrm dV$

which is 2 times the volume of the hemisphere $H$ , so that the net flux is $\boxed{4\sqrt3\pi}$ . Just to confirm, we could compute the integral in spherical coordinates:

$\displaystyle2\int_0^{\pi/2}\int_0^{2\pi}\int_0^{\sqrt3}\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=4\sqrt3\pi$

4 0

4 years ago

Number 23 please answer

vfiekz [6]

I dont see a picture... :(

5 0

3 years ago