Answer:
Step-by-step explanation:
Given ,
A right angle triangle ΔABC with right angle at C and ∠A=30° and AC=5√5 units .
Let ∠A=A,∠B=B∠C=C and AC=b,BC=a,CA=b .
Implies perimeter of triangle = a+b+c .
now
![tanA=\frac{a}{b} \\\a=b*tanA\\a= 5\sqrt{5} *tan30^0\\a=\frac{5\sqrt{5}}{\sqrt{3}}](https://tex.z-dn.net/?f=tanA%3D%5Cfrac%7Ba%7D%7Bb%7D%20%5C%5C%5Ca%3Db%2AtanA%5C%5Ca%3D%205%5Csqrt%7B5%7D%20%2Atan30%5E0%5C%5Ca%3D%5Cfrac%7B5%5Csqrt%7B5%7D%7D%7B%5Csqrt%7B3%7D%7D)
and
![cosA=\frac{b}{c} \\\c=\frac{b}{cosA} \\c=\frac{10\sqrt{5}}{\sqrt{3} }](https://tex.z-dn.net/?f=cosA%3D%5Cfrac%7Bb%7D%7Bc%7D%20%5C%5C%5Cc%3D%5Cfrac%7Bb%7D%7BcosA%7D%20%5C%5Cc%3D%5Cfrac%7B10%5Csqrt%7B5%7D%7D%7B%5Csqrt%7B3%7D%20%7D)
implies ,
![perimeter = \frac{5\sqrt{5}}{\sqrt{3}} + 5\sqrt{5} +\frac{10\sqrt{5}}{\sqrt{3} }\\perimeter= 5\sqrt{15} + 5\sqrt{5}](https://tex.z-dn.net/?f=perimeter%20%3D%20%5Cfrac%7B5%5Csqrt%7B5%7D%7D%7B%5Csqrt%7B3%7D%7D%20%2B%205%5Csqrt%7B5%7D%20%2B%5Cfrac%7B10%5Csqrt%7B5%7D%7D%7B%5Csqrt%7B3%7D%20%7D%5C%5Cperimeter%3D%205%5Csqrt%7B15%7D%20%2B%205%5Csqrt%7B5%7D)
An equivalent ratio of the given ratio 6/7 is; 12/14
<h3>How to find Equivalent Ratios?</h3>
To find equivalent ratios, we will just multiply the given ratio by any number that is equivalent to 1 such as 2/2, 3/3, 4/4, 5/5 e.t.c
Now, we want to find equivalent ratio of 6/7. Applying the procedure above, we can say that;
Equivalent ratio = (6/7) * (2/2) = 12/14
Thus, an equivalent ratio of 6/7 is; 12/14
Read more about Equivalent Ratios at; brainly.com/question/2328454
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15% of $70
do 15 over 100 then put 70 as your denominator cross multiply
15 times 70 =1,050 divided by 100 = [10.50 <--- answer]
70.00-10.50=59.50
Answer:
see below
Step-by-step explanation:
![\huge14 {x}^{ 5 } = 2 {x}^{3} . \boxed{7 {x}^{2} }](https://tex.z-dn.net/?f=%20%5Chuge14%20%7Bx%7D%5E%7B%205%20%7D%20%20%3D%202%20%7Bx%7D%5E%7B3%7D%20.%20%5Cboxed%7B7%20%7Bx%7D%5E%7B2%7D%20%7D)