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Bond [772]
3 years ago
8

7) A store has a sale for 10% off. You decide to buy a $17 DVD.

Mathematics
1 answer:
kondaur [170]3 years ago
8 0

Answer:

you save 1.70 and spend 15.30

Step-by-step explanation:

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4(5f + 9)
Marina86 [1]

Answer: hopes this helps i spent a lot of time on it !!!:)lol

2 0 + 3 6

− 8 − 1 2

2 0 + 1 0

1 0 ℎ − 1 5

− 1 2 − 1 4

5 6 − 6 3

8 − 1 8

− 8 + 1 2

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Calculus question....does anyone know how to solve this?
iogann1982 [59]
h(x)=(f\circ g)(x)
\sqrt{x+5}=\sqrt{g(x)+2}
x+5=g(x)+2
g(x)=x+3

Just to check this is correct:

(f\circ g)(x)=f(g(x))=f(x+3)=\sqrt{(x+3)+2}=\sqrt{x+5}=h(x)
6 0
3 years ago
What is the scale factor for pre-image IJKH to image MNOL?
solniwko [45]

Answer:

Step-by-step explanation:

Given are two rectangles MNOL and IJKH

MNOL is the image and IJKH is the preimage.

OBviously similarity is preserved between these.

Hence sides will be proportional

i.e. l1/l2 = w1/w2 = Scale factor k

This can also be written as

Scale factor square = k^2=\sqrt{ \frac{areaI}{area2} }

Scale factor = square root of ratio of rectangle areas

Find ratio as

\frac{375}{135} =\frac{25}{9}

k = Scale factor = square root of the above fraction

=\frac{5}{3}

5 0
4 years ago
A pendulum is 18 feet long. Its central angle is 44º. The pendulum makes one back and forth swing every 12 seconds. Each minute,
expeople1 [14]
Radius: r=18 feet
Cental Angle: A=44°
Each cycle (one back and forth) lasts 12 seconds
In each cycle the pendulum swings:
L=(A/360°) 2 pi r
L=(44°/360°)(2)(3.141592654)(18 feet)
L=(0.122222222)(113.0973355 feet)
L=13.82300764 feet
Rounded to 3 decimal places:
L=13.823 feet

Each minute (60 seconds) the pendulum makes:
Number of cycles: n=(60 seconds) / (12 seconds)→n=5 cycles

Then, each minute, the pendulum swings:
T=nL=5(13.823 feet)→T=69.115 feet

Answer: Each minute, the pendulum swings 69.115 feet. 
8 0
3 years ago
Calculate the second moment of area of a 4-in-diameter shaft about the x-x and yy axes, as shown.
Keith_Richards [23]
Second moment of area about an axis along any diameter in the plane of the cross section (i.e. x-x, y-y) is each equal to (1/4)pi r^4.
The second moment of area about the zz-axis (along the axis of the cylinder) is the sum of the two, namely (1/2)pi r^4.

The derivation is by integration of the following:
int int y^2 dA
over the area of the cross section, and can be found in any book on mechanics of materials.

6 0
3 years ago
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