7) A store has a sale for 10% off. You decide to buy a $17 DVD.

Expand and simplify: (x-5)(x+5)

stealth61 [152]

X^2-5x+5x-25 (multiply (x-5) with (x+5))
X^2-25 ( -5x+5x =0)

5 0

3 years ago

Read 2 more answers

How do you find the area of each regular polygon

Alex73 [517]

If the drawing of your octagon (or whatever) has been separated into triangles, and one triangle's area<span> is labeled, then you do not need to know the apothem. Just take the </span>area<span> of that one triangle, and multiply by the number of sides in the original </span>polygon<span>.</span>

5 0

2 years ago

What is thr inverse of f(x) if the function is x=-4,-2,0,2,4 f(x)=-2,-1,0,1,2

Lorico [155]

For a function, if it has an inverse function, keep in mind that, the "domain of the original, is the range of the inverse, and the range of the original, is the domain of the inverse", what the dickens does that mean?

well, it means the values for "x" and f(x), on the inverse, are the same values, but swapped up, therefore

$\bf \stackrel{original~function}{\begin{array}{ccll}
x&f(x)\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
-4&-2\\
-2&-1\\
0&0\\
2&1\\
4&2
\end{array}}\qquad \qquad \qquad 
\stackrel{inverse~function}{\begin{array}{ccll}
x&f(x)\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
-2&-4\\
-1&-2\\
0&0\\
1&2\\
2&4
\end{array}}$

7 0

2 years ago

1) 130 words in 5 mins. How many words in an hour?

FinnZ [79.3K]

Answer:

Part 1) 1,560 words

Part 2) 161 miles

Step-by-step explanation:

Part 1) 130 words in 5 mins. How many words in an hour?

Remember that

$1\ hour=60\ min$

so

using proportion

Find out how many words in 60 minutes (one hour)

$\frac{130}{5}\ \frac{words}{min}= \frac{x}{60}\ \frac{words}{min}\\\\x=130(60)/5\\\\x=1,560\ words$

Part 2) 322 miles in 2 hours. How many miles in 60 minutes?

Remember that

$1\ hour=60\ min$

so

$2\ hours=120\ minutes$

using proportion

Find out how many miles in 60 minutes

$\frac{322}{120}\ \frac{miles}{min}= \frac{x}{60}\ \frac{miles}{min}\\\\x=322(60)/120\\\\x=161\ miles$

8 0

2 years ago

A recent study found that the average length of caterpillars was 2.8 centimeters with a

pogonyaev

Using the normal distribution, it is found that there is a 0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, the mean and the standard deviation are given, respectively, by:

$\mu = 2.8, \sigma = 0.7$ .

The probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters is <u>one subtracted by the p-value of Z when X = 4</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{4 - 2.8}{0.7}$

Z = 1.71

Z = 1.71 has a p-value of 0.9564.

1 - 0.9564 = 0.0436.

0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

More can be learned about the normal distribution at brainly.com/question/24663213

#SPJ1

4 0

2 years ago