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3 years ago

What is a prime factorization of 42 pls help :)

Mathematics

1 answer:

Darya [45]3 years ago

7 0

Answer:

6,7

Step-by-step explanation:

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PLZ HELP ME 4 min left 50 points and brainleist

valentina_108 [34]

Answer:

y= -6

Step-by-step explanation:

4y=2(y−5)−2

4y = 2y -10 -2

4y = 2y -12

2y = -12

y = -6

7 0

3 years ago

What part of the expression below should be calculated first?

Lostsunrise [7]

C ,in the most parenthesis

8 0

3 years ago

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Change to log form. <br> 7e^(-x)=0.01

sladkih [1.3K]

(0.00142857)=-x is your answer

3 0

3 years ago

Find the dimensions of an open rectangular box with a square base that holds 2000 cubic cm and is constructed with the least bui

Vesnalui [34]

<h3>The dimensions of the given rectangular box are:</h3><h3>L = 15.874 cm , B = 15.874 cm , H = 7.8937 cm</h3>

Step-by-step explanation:

Let us assume that the dimension of the square base = S x S

Let us assume the height of the rectangular base = H

So, the total area of the open rectangular box

= Area of the base + 4 x ( Area of the adjacent faces)

= S x S + 4 ( S x H) = S² + 4 SH ..... (1)

Also, Area of the box = S x S x H = S²H

⇒ S²H = 2000

$\implies H = \frac{2000}{S^2}$

Substituting the value of H in (1), we get:

$A = S^2 + 4 SH = S^2 + 4 S(\frac{2000}{S^2}) = S^2 + (\frac{8000}{S})\\\implies A = S^2 + (\frac{8000}{S})$

Now, to minimize the area put :

$(\frac{dA}{dS} ) = 0 \implies 2S - \frac{8000}{S^2} = 0\\\implies S^3 = 4000\\\implies S = 15.874 \approx 16 cm$

Putting the value of S = 15.874 cm in the value of H , we get:

$\implies H = \frac{2000}{S^2} = \frac{2000}{(15.874)^2} = 7.8937 cm$

Hence, the dimensions of the given rectangular box are:

L = 15.874 cm

B = 15.874 cm

H = 7.8937 cm

3 0

3 years ago

Simplify 3/8+3/5 Btw these are fractions thats why I put a /

tangare [24]

3/8 + 3/5 = <u>39/40</u> and 39/40 Can't be <em>simplified</em>

4 0

3 years ago

Read 2 more answers