What is a prime factorization of 42 pls help :)

NISA [10]

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6 0

2 years ago

Read 2 more answers

Please Help!!! Will give brainliest

qaws [65]

36 cm^2

Step-by-step explanation:

Small window

Length: 2cm

Width: 2cm

Area: 4 cm^2

Big window

Length: 4cm

Width: 3cm

Area: 12 cm^2

Total area of the windows:

(Area of 4 small windows + area of 1 big window)

(4 cm^2 x 4 + 12cm^2)

= 28 cm^2

Above window (approx.)

Rectangle

Length: 3cm

Width: 2cm

Area: 6 cm^2

Triangle

Base: 1cm

Height: 1cm

Area: 2 x 0.5 cm^2 = 1 cm^2

Square (between the triangles)

Length: 1cm

Width: 1cm

Area: 1 cm^2

= 8 cm^2

TOTAL AREA OF ALL WINDOWS

= AREA OF 4 WINDOWS + AREA OF BIG WINDOW + AREA OF ABOVE WINDOW

= 16 cm^2 + 12 cm^2 + 8 cm^2

I hope I made the explanations clear enough to make it easier for you to understand!

8 0

1 year ago

Mr. Vara is designing post caps in the shape of a square pyramid for a fence that he just built in his backyard. The caps are so

Lyrx [107]

Answer:

Height of the square pyramid is 6.569 centimeter

Step-by-step explanation:

The volume of the square pyramid is 94.5 cubic centimeters

The height of the square pyramid will be equal to the lengths of the sides of the square.

The volume of the square pyramid is given by

$a^2 * \frac{h}{3}$

or

$\frac{a^3}{3} = 94.5\\a^3 = 94.5 *3\\a = \sqrt[3]{94.5*3} \\a = 6.569$ centimeter

Height of the square pyramid is 6.569 centimeter

3 0

3 years ago

A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f

Andrews [41]

Answer:

$A = \frac{P}{r}\left( e^{rt} -1 \right)$

Step-by-step explanation:

This is a separable differential equation. Rearranging terms in the equation gives

$\frac{dA}{rA+P} = dt$

Integration on both sides gives

$\int \frac{dA}{rA+P} = \int dt$

where $c$ is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

$\int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c$