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elena55 [62]
3 years ago
12

%3D%20%20-%20%28x%20-%203%29%20%2B%204%20" id="TexFormula1" title=" \frac{1}{2}(2 - 6x) - 4(x + \frac{3}{2}) = - (x - 3) + 4 " alt=" \frac{1}{2}(2 - 6x) - 4(x + \frac{3}{2}) = - (x - 3) + 4 " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
Art [367]3 years ago
4 0

Answer:

x=-2

Step-by-step explanation:

1/2(2-6x)-4(x+3/2)=-(x-3)+4

(1-3x)-4x-6=-x+3+4

-7x-5=-x+7

Tranpose

-7x+x=5+7

-6x=12

Divide by -6

x=-2

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Write the inequality represented by the graph below.
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The image point of A after a translation right 4 units and up 3 units is the point
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Answer:

(--6,-1)

Step-by-step explanation:

Right 4 units, to go back, left 4 units

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4 0
3 years ago
If 36 inches equals 1 yard then 2 1/3 yard equals how many inches
aniked [119]
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7 0
3 years ago
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P: x – 5 =10 q: 4x + 1 = 61 Which is the inverse of p → q?
Lesechka [4]
The inverse is b.  If 4x+1 .NE. 61, then x-5 .NE.10
3 0
3 years ago
Read 2 more answers
2x2 – 9x + 2 = –1
Reika [66]

Answer:

C)  The discriminant is greater than 0, so there are two real roots

Step-by-step explanation:

<u>Discriminant</u>

b^2-4ac\quad\textsf{when}\:ax^2+bx+c=0

\textsf{when }\:b^2-4ac > 0 \implies \textsf{two real roots}

\textsf{when }\:b^2-4ac=0 \implies \textsf{one real root}

\textsf{when }\:b^2-4ac < 0 \implies \textsf{no real roots}

2x^2-9x+2=-1

\implies 2x^2-9x+3=0

\implies a=2, b=-9, c=3

\begin{aligned}b^2-4ac &=(-9)^2-4(2)(3)\\& =81-24\\&=57 > 0\implies \textsf{two real roots}\end{aligned}

5 0
2 years ago
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