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2 years ago

X intercept Of v^2 +5v+6=0

Mathematics

1 answer:

postnew [5]2 years ago

3 0

Answer:

<h2>x-intercepts:</h2><h2>x = -2 and x = -3 ⇒ (-2, 0) and (-3, 0).</h2>

Step-by-step explanation:

$f(v)=v^2+5v+6\\\\\text{The x-intercept is for y = 0.}\\\\v^2+5v+6=0\\\\v^2+2v+3v+6=0\\\\v(v+2)+3(v+2)=0\\\\(v+2)(v+3)=0\iff v+2=0\ \vee\ v+3=0\\\\v+2=0\qquad\text{subtract 2 from both sides}\\v=-2\\\\v+3=0\qquad\text{subtract 3 from both sides}\\v=-3$

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The sum of three consecutive odd integers is -75. What is the smallest number

pashok25 [27]

Answer:

-27

Step-by-step explanation:

First, let's call the smallest number: n

Then, the next two consecutive odd numbers would be:

n+2 and n+4 (this is because it's only odd numbers so we add 2)

We know the sum of these is −75 so we can write this equation and solve for n:

n + (n + 2) + (n + 4) = -75

n + n + 2 + n + 4 = -75

n + n + n + 2 + 4 = -75

n + n + n + 6 = -75

1n + 1n + 1n + 6 = -75

3n + 6 = -75 Subtract 6 from each side, which cancels the 6 on the left.

3n + 6 - 6 = -75 - 6

3n = -75 - 6

3n = -81 Divide each side by 3

3n/3 = -81/3

n = -81/3

n = -27

n + 2 = -27 + 2 = -25

n + 4 = -27 + 4 = -23

The 3 consecutive odd integers would be:

-27, -25, -23

Let's check our work:

-27 + -25 + -23 = -75 We are correct!

The smallest number is -27

3 0

2 years ago

2/3 x - 4 equal negative 2

Fiesta28 [93]

Answer:

x = 3

Step-by-step explanation:

Given

$\frac{2}{3}$ x - 4 = - 2

Multiply through by 3 to clear the fraction

2x - 12 = - 6 ( add 12 to both sides )

2x = 6 ( divide both sides by 2 )

x = 3

5 0

3 years ago

HELP! HOW DO I DO THIS???

inna [77]

A b c and d r not answers, u need to tell how the different variations would change based on the numbers and where they r

8 0

2 years ago

Am i correct? will mark brainliest

lana [24]

Answer:

no, its 11 for the first one and 45 for the second

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

taurus [48]

Answer:

$x^2 - 2x + 10$ , option B

Step-by-step explanation:

Complex numbers:

The most important relation that involves complex numbers is given by:

$i^2 = -1$

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

The solutions are:

$x_1 = 1 - 3i, x_2 = 1 + 3i$

We have to find the polynomial. All option have $a = 1$ . So

$(x - (1 - 3i))(x - (1 + 3i)) = x^2 - x(1 + 3i) - x(1 - 3i) + (1 - 3i)(1 + 3i) = x^2 - x -3ix - x + 3ix + 1^2 - (3i^2) = x^2 - 2x + 1 - 9i^2 = x^2 - 2x + 1 - 9(-1) = x^2 - 2x + 10$

The correct answer is given by option b.

6 0

3 years ago