Hello :
the tangent has same slope of the line 16x -y +5 = 0 because parallel.
y = 16x + 5
the slope is : 16
but : f'(x) = 16
f'(x) = 16x^3 - 16x +16
solve : 16x^3 - 16x +16 = 16
x^3 - x +1 =1
x^3 - x = 0
x(x² - 1 ) =0
x(x -1 )(x +1) =0
x=0 or x-1 =0 or x +1= 0
x=0 or x = 1 or x = -1
if : x = 0 : y = 4(0)^4 -8(0)^2+16(0) +7 =7
if : x =1 : y = 4(1)^4 -8(1)^2+16(1) +7 = 19
if : x = -1 : y = 4(-1)^4 -8(-1)^2+16(-1) +7 = -13
<span>the points : A(0,7) , B(1 , 19) , c ( -1 , -13)</span>
Answer:
x=2ln(2)/(2ln(2)-ln(3))
Step-by-step explanation:
ln(4^x-1)=ln(3^x)
(x-1)ln(4)=ln(3^x)
(x-1)ln(4)=xln(3)
ln(4)x-ln(4)=xln(3)
ln(4)x=ln(3)x+2ln(2)
2ln(2)x-ln(3)x=2ln(2)
(2ln(2)-ln(3))x=2ln(2)
Therefore, x=2ln(2)/(2ln(2)-ln(3))
The answer is 4. Since 12+ 12 = 24, I added 4 + 4, which made 42.
So the length of the width of the rectangle is 4.
Hope this helps!
