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Eduardwww [97]
3 years ago
12

If the altitude of an isosceles right triangle has a length of x units, what is the length of one leg of the large right triangl

e in terms of x?
A) x units
B) x square root of 2 units
C) x square root of 3 units
D) 2x units

Mathematics
2 answers:
gulaghasi [49]3 years ago
6 0
Check the picture below.

bear in mind that, if the right-triangle is an isosceles, is a 45-45-90 triangle, and if we split it from the "vertex" above perpendicular to the base, we end up with two more 45-45-90 triangles.

const2013 [10]3 years ago
6 0

Answer:

B) x square root of 2 units

Step-by-step explanation:

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80.75 / 8.50 = 9.5
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Create a matrix for this system of linear equations, The determinant of the coefficient matrix is
marin [14]

Answer:  The determinant of the coefficient matrix is -15 and x = 3, y = 4, z = 1.

Step-by-step explanation:  The given system of linear equations is :

2x+y+3z=13~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\x+2y=11~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)\\\\3x+z=10~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)

We are given to find the determinant of the coefficient matrix and to find the values of x, y and z.

The determinant of the co-efficient matrix is given by

D=\begin{vmatrix}2 & 1 & 3\\ 1 & 2 & 0\\ 3 & 0 & 1\end{vmatrix}=2(2-0)+1(0-1)+3(0-6)=4-1-18=-15.

Now, from equations (ii) and (iii), we have

x+2y=11~~~~~\Rightarrow y=\dfrac{11-x}{2}~~~~~~~~~~~~~~~~~~~~~~~~~~(iv)\\\\\\3x+z=10~~~~~~\Rightarrow z=10-3x~~~~~~~~~~~~~~~~~~~~~~~~~(v)

Substituting the value of y and z from equations (iv) and (v) in equation (i), we get

2x+y+3z=13\\\\\Rightarrow 2x+\dfrac{11-x}{2}+3(10-3x)=13\\\\\Rightarrow 4x+11-x+60-18x=26\\\\\Rightarrow -15x+71=26\\\\\Rightarrow -15x=26-71\\\\\Rightarrow -15x=-45\\\\\Rightarrow x=3.

From equations (iv) and (v), we get

y=\dfrac{11-3}{2}=4,\\\\z=10-3\times3=1.

Thus, the determinant of the coefficient matrix is -15 and x = 3, y = 4, z = 1.

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3 0
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1 2/5m-3/5(2/3m+1) How do you solve this problem
igor_vitrenko [27]

Step-by-step explanation:

I am not sure what you mean by "solve".

I assume you mean simplify the expression.

and then it is very tricky to find the true original expression the way you typed it.

I think you meant

1 2/(5m) - 3/(5(2/(3m + 1)))

1 = 5m/5m

1 2/(5m) = (5m+2)/5m

3/(5(2/(3m + 1))) = 3/(10/(3m + 1)) = 3/1 / (10/(3m + 1))

when dividing by a fraction, it is the same as multiplying with the upside-down fraction

so, this is the same as

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this would give us in total

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to do the subtraction we need to bring both fractions to the save denominator (lower part).

it seems to me the easiest one would be 10m.

so,

2×(5m + 2)/10m - m×(9m + 3)/10m =

= (10m + 4)/10m - (9m² + 3m)/10m =

= (10m + 4 - 9m² - 3m)/10m = (-9m² + 7m + 4)/10m

if we want to transform this back to a sum of fractions :

4/10m - (9m² - 7m)/10m = 2/5m - (9m - 7)/10

5 0
2 years ago
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