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Katarina [22]
3 years ago
11

Find an explicit rule for the nth term of the sequence. 7, -7, 7, -7, ...

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
6 0
Try a_n=7(-1)^{n+1}, where n\ge1.
You might be interested in
Number 27.
atroni [7]
<h3>Answer:</h3>

none of these has "no solution"

<h3>Explanation:</h3>

A. The solution is (8/3, 3)

B. The second equation is -1/2 times the first, so these describe the same line. The system has an <em>infinite number of solutions</em>.

C. The solution is (-4, -2)

D. The solution is (4, -2)

E. The second equation is 2 times the first, so these describe the same line. The system has an <em>infinite number of solutions</em>.

_____

A system of equations will have "no solution" when it describes parallel lines—lines that do not intersect. In standard form, such equations are recognizable by their different constants. For example,

  • 3x -4y = -4
  • 3x -4y = 20 . . . . . . 20 is different from -4

have different constants, so the equations describe parallel lines.

We could multiply one of these by -2 and the system would still be "inconsistent"—having no solution.

  • 3x -4y = -4
  • -6x +8y = -40
5 0
3 years ago
Help and if you actually answer I'll give you brainliest​
schepotkina [342]

Answer:

1) 2/3

2) 1/2

3) 4/5

4) 3/4

Step-by-step explanation:

4/6 can be divided by 2 to get 2/3 in its simplest

2/4 can be divided by 2 to get 1/2 in its simplest

12/15 can be divided by 3 to get 4/5 in its simplest

6/8 can be divided by 2 to get 3/4 in its simplest

6 0
2 years ago
Read 2 more answers
Julio and his friend ordered five pizzas they know that 1/3 of a pizza will serve one person how many servings are there? Please
Ket [755]
Okay, so if 1/3 of a pizza is a serving, you would have to know that 1 pizza contains 3 servings. 

Multiply 5*3 for your answer.

5*3= 15

That is 15 servings. 

I hope this helped you!

Brainliest answer would be appreciated!
5 0
3 years ago
(Essay Question 7 Points)
Irina18 [472]

Well I don't know.
Let's think about it:

-- There are 6 possibilities for each role.
    So 36 possibilities for 2 rolls.
    Doesn't take us anywhere.

New direction:
-- If the first roll is odd, then you need another odd on the second one.
-- If the first roll is even, then you need another even on the second one.
This may be the key, right here !

-- The die has 3 odds and 3 evens.

-- Probability of an odd followed by another odd = (1/2) x (1/2) = 1/4
-- Probability of an even followed by another even = (1/2) x (1/2) = 1/4

I'm sure this is it.  I'm a little shaky on how to combine those 2 probs.

Ah hah ! 
Try this:

Probability of either 1 sequence or the other one is (1/4) + (1/4) = 1/2 .

That means ... Regardless of what the first roll is, the probability of
the second roll matching it in oddness or evenness is 1/2 .

So the probability of 2 rolls that sum to an even number is 1/2 = 50% .

Is this reasonable, or sleazy ?


4 0
3 years ago
Camilo estimates the weight of the dog . The veterinarian says that the dog weighs 84 pounds . The percent error in Camillo's es
blsea [12.9K]

Answer:

The estimated weight is in the range:

75.6 pounds \leq Weight \leq 92.4 pounds

Step-by-step explanation:

Since, the maximum error is 10%.

Therefore, the maximum and minimum vales will be 10% more and 10% less than 84 pounds, respectively.

<u>For Maximum Limit</u>:

Weight_{max} = (1.1)(84 pounds)

Weight_{max} = <u>92.4 pounds</u>

<u>For Minimum Limit</u>:

Weight_{min} = (0.9)(84 pounds)

Weight_{min} = <u>75.6 pounds</u>

Hence, the estimated weight is in the range:

75.6 pounds \leq Weight \leq 92.4 pounds

5 0
3 years ago
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