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Hunter-Best [27]
3 years ago
11

Glenn bought 3 pounds of tomatoes. He used 5/8 of them to make sauce.

Mathematics
1 answer:
n200080 [17]3 years ago
4 0

<em>Question Continuation:</em>

<em>Glenn bought 3 pounds of tomatoes. He used 5/8 of them to make sauce. </em>

<em>Make an equation that shows the number of pounds of tomatoes Glenn used for the sauce.</em>

<em></em>

Answer:

y = \frac{15}{8}\ lb

Step-by-step explanation:

Given

Weight of Tomato = 3 lb

Used Proportion = 5/8

Required

Determine the portion used

To solve this we simply multiply the used proportion by the weight of the tomato bought

Represent the used portion with y.

So:

y = Weight * Used\ Proportion

y = 3\ lb * \frac{5}{8}

y = \frac{15}{8}\ lb

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A rectangular piece of card has a perimeter of 40cm and width of 8cm.
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Answer:

Area of the rectangular piece of card = 96 sq.cm

Step-by-step explanation:

here we go,

peremeter ( p ) = 2 × ( length (L) + width (B) )

so,

=》40 = 2 ( L + 8 )

=》40 / 2 = L + 8

=》20 = L + 8

=》L = 20 - 8

=》L = 12

so, length of the card = 12cm

now,

Area (A) = length (L) × width (B)

=》A = 12 × 8

=》Area = 96 sq.cm

3 0
3 years ago
Emma spent $35.22 on 3 dozen bagels and a gallon of iced tea. The price of the gallon of iced tea was $5.25. The following equat
amm1812

Answer:

9.99

Step-by-step explanation:

Subtract 5.25 on both sides

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Hope this helps!


4 0
3 years ago
1.Simplify 5 to the 5th over 5 to the 8th.
timurjin [86]
Q1. The answer is <span>1 over 5 to the 3rd power.

</span>5 to the 5th is 5⁵
5 to the 8th is 5⁸
5 to the 5th over 5 to the 8th is \frac{ 5^{5} }{ 5^{8} }
To simplify, we will use two rules: 
\frac{ x^{a}}{ x^{b} } = x^{a-b} \\ x^{-a} = \frac{1}{ x^{a}}
Therefore:
\frac{ 5^{5} }{ 5^{8} } = 5^{5-8} =5^{-3}= \frac{1}{5^{3}}
\frac{1}{5^{3}} is the same as 1 over 5 to the 3rd power.


Q2. The answer is <span>(53)−4.

The exponents are multiplied when are expressed in the form:
</span>(x^{a}) ^{b}= x^{a*b}
So, (5^{3} )^{-4}=5^{3*(-4)}=5^{-12}

Other choices are incorrect:
<span>one third to the 4th times one third to the 7th is </span>( \frac{1}{3} )^{4} *( \frac{1}{3} )^{7}=( \frac{1}{3} )^{4+7}
3 to the 7th over 3 to the 15th is \frac{ 3^{7} }{3^{15}} =3^{7-15}
<span>45 ⋅ 42 is </span>4^{5}* 4^{2} =  4^{5+2}
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