What is 5(h-4)=8?????????????????????

200 grams of fertilizer are used for each tree in an orchard containing 1200 trees. at $2.75 per kilogram of fertilizer, how muc

stiks02 [169]

To determine the cost to fertilize the trees, you need to figure out how many kilograms of fertilizer are needed. With the information given, you can determine The number of grams needed to fertilize 1200 trees. To do this you would multiply 200 times 1200. This equals 240,000 grams. To convert this to kilograms, divide 240000g by 1000 g. Every group of 1000 g is 1 kg. The answer is 240 kilograms. Multiply 240 kg by the price of $2.75 per kilogram to get $660 as the cost.

4 0

3 years ago

Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete

icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 17 means that $N = 17$

4 are carrying nucleas weapons, which means that $k = 4$

9 are destroyed, which means that $n = 9$

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X > 1) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294$

$P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412$

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588$

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

8 0

3 years ago

Find the area of the shape below. Plz help!!!

skelet666 [1.2K]

Answer:

A = 108 units²

Step-by-step explanation:

The area (A) of a trapezium is calculated as

A = $\frac{1}{2}$ h (b₁ + b₂ )

where h is the height between the 2 bases and b₁, b₂ are the parallel bases

Here h = 24 , b₁ = 8 , b₂ = 1 , then

A = $\frac{1}{2}$ × 24 × (8 + 1) = 12 × 9 = 108 units²

5 0

3 years ago

Given z1 and z2 below. Calculate z1/z2 and write your answer in rcistheta form.

andre [41]

Answer:

(2/9)cis(30°)

Step-by-step explanation:

We can express the two numbers in magnitude∠angle form, then find their ratio.

|z1| = 3√((-1)² +(√3)²) = 3√4 = 6

∠z1 = arctan((3√3)/(-3)) = -arctan(√3) = 120°

z2 = 27∠90°

So, the ratio is ...

z1/z2 = (6∠120°)/(27∠90°) = (6/27)∠(120°-90°)

z1/z2 = (2/9)∠30°

8 0

3 years ago

Can somebody help plz it’s due soon?

Snezhnost [94]

The answer is 7/18, basically the amount of people in favour over the Amon t of people in total :)

8 0

3 years ago