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tatiyna
3 years ago
14

Si tienes un rectángulo de área igual a x2 + 5x¿Cuál de las siguientes factorizaciones nos presenta el producto de la base por l

a altura de ese rectángulo? *
a) ( x + 5 ) ( x – 5 )

b) ( 5x ) ( x + 1 )

c) ( x ) ( x – 5 )

d) ( x + 5 ) ( x )
Mathematics
1 answer:
Softa [21]3 years ago
7 0

Answer: factorizar x de x ^ 2 + 5x.

x (x + 5)

Step-by-step explanation:

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On a blueprint, the scale indicates that 8 cm represent 16 feet. What is the length of a room that is 8.8 cm long and 3 cm wide
lana [24]
For the answer to the question above asking wWhat is the length of a room that is 8.8 cm long and 3 cm wide on the blueprint if <span>a blueprint, the scale indicates that 8 cm represent 16 feet?
</span>The room is 22.4 feet long

8cm=16ft
9.8cm=?ft

  8cm       9.8cm
______=______
  16ft          x ft

Cross multiply
8x=156.8
divide both sides by 8
x=19.6 ft
4 0
3 years ago
The 3kg object in Figure is released from rest at a height of on a curved frictionless ramp.
yanalaym [24]

The object compresses the spring up to 0.8577m.

<h3>What is Potential Energy?</h3>

Potential Energy is the energy possessed by an object at rest.

The object is falling from the rest and it is assumed that the friction on the ramp is zero and the air resistance is also considered to be zero so only the gravitational force acts and the total potential energy gets converted to Kinetic Energy.

The total amount of potential energy at the top of the ramp is given by

Ep=mgh

Ep=3 * 9.81 *5

Ep=147.15 Joules

This is equal to kinetic energy.

From the formula for elastic potential energy

The distance up to which the spring is compressed is determined

The force constant = 400N/m

147.15 =(1/2)k(x²)

294.3=(400)(x²)

0.73575=x²

x=0.8577 m

So, the object compresses the spring up to 0.8577m.

  • When the object compresses the spring, the potential energy of the spring is converted into Kinetic Energy so it will push the object back again.

To know more about Potential Energy

brainly.com/question/24284560

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3 0
1 year ago
An airplane travels about 1,500 Km in a straight line between Toronto and Winnipeg. However, the plane must climb to 10,000 m du
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Answer:416

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The climb distance is:200 * Sec [ArcTan [10/200]] = 10√ 401 km

and the decent distance is:300 * Sec [ArcTan [10/300]] = 10√901 km

So add the given results above with 500 km and this will be the additional distance that plane moves through the air.

The answer would be in the unit meters.

((10√401 +10√901−500)∗1000)=416 meters

Hope this is the answer that you are looking for.

7 0
2 years ago
What does x equal if the equation is x+2.62=6.37
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Answer:

x=3.75

The drawing will help

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