The Answer to question is 2.05
Answer:
A
Step-by-step explanation:
it would be A because a necessity would be getting food from the grocery store
by the double angle identity for sine. Move everything to one side and factor out the cosine term.
Now the zero product property tells us that there are two cases where this is true,
In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of
, so
where
![n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}](https://tex.z-dn.net/?f=n%5B%2Ftex%20%5Dis%20any%20integer.%5C%5CMeanwhile%2C%5C%5C%5Btex%5D10%5Csin%20x-3%3D0%5Cimplies%5Csin%20x%3D%5Cdfrac3%7B10%7D)
which occurs twice in the interval
for
and
. More generally, if you think of
as a point on the unit circle, this occurs whenever
also completes a full revolution about the origin. This means for any integer
, the general solution in this case would be
and
.
Answer:
x = 15
y = 15√3
Step-by-step explanation:
This is a special right triangle with angle measures 30° 60° 90°
The side lengths should be x 2x x√3
If the measure of hypotenuse 30 then the side length that sees 30° should be half of it so x = 15 and y = 15√3
All the triangles are isosceles meaning that they have to sides that are equal
