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mina [271]
2 years ago
10

Which expression is equivalent to 4(3+5)-3.94?

Mathematics
1 answer:
Anna007 [38]2 years ago
3 0

Answer:

4(3 + 5) - 3.94 \\ 4 \times 8 - 3.94 \\ 32 - 3.94 \\  = 28.06

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F∧-1(-2)<br> i need help solving this f to -1 power times -2
elena-14-01-66 [18.8K]

The solution is f².

<h3>How to solve for this</h3>

The question that we have here is of the form f to -1 power times -2. To have a better graphic image we can rewrite it as

f^-^1^(^-^2^)

Now we have to multiply the powers -1 and -2

Remember that in the rules of mathematics, the solution for -1 and -1 = 1

This tells us that - * - = +

Hence we would have -1 * -2

= 2

Therefore the power would be f²

<h3>How do you simplify exponents and powers?</h3>

In order to carry out the simplification of exponents what you have to do would be the multiplication of the exponents that are in the question. The base of the question remains unchanged.

For example, (2³)⁵ = 2³ˣ⁵ = 2¹⁵. For any positive number x and integers a and b: (x^a)^b = x^a^.^b

The exponents here are the numbers that are written above the base. They usually tell us how many times the base would have to be multiplied by itself to get a  solution.

Read more on multiplication of powers here:

brainly.com/question/26130878

#SPJ1

4 0
1 year ago
The graph shows the amount of money Miguel earns after working x hours.
kotegsom [21]

Answer:

13 dollars per hour ! ^^

Step-by-step explanation:

7 0
3 years ago
Expand and simply (x + 3) (x + 5)
kifflom [539]
Here’s the answer :)

4 0
3 years ago
I don't get it please help.
pshichka [43]

Answer:

Answer

Step-by-step explanation:

y=-2/7x+5=

slope: -2/7

y-intercept: (0,5)

I think it's what the question is if not then sorry.

8 0
3 years ago
Plzzz help me with this I’ll give brainliest
scoray [572]

Answer18:

The quadrilateral ABCD is not a parallelogram

Answer19:

The quadrilateral ABCD is a parallelogram

Step-by-step explanation:

For question 18:

Given that vertices of a quadrilateral are A(-4,-1), B(-4,6), C(2,6) and D(2,-4)

The slope of a line is given m=\frac{Y2-Y1}{X2-X1}

Now,

The slope of a line AB:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{6-(-1)}{(-4)-(-4)}

m=\frac{7}{0}

The slope is 90 degree

The slope of a line BC:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{6-6}{(-4)-(-1)}

m=\frac{0}{(-3)}

The slope is zero degree

The slope of a line CD:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{(-4)-6}{2-2}

m=\frac{-10}{0}

The slope is 90 degree

The slope of a line DA:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{(-1)-(-4)}{(-4)-(2)}

m=\frac{3}{-6}

m=\frac{-1}{2}

The slope of the only line AB and CD are the same.

Thus, The quadrilateral ABCD is not a parallelogram

For question 19:

Given that vertices of a quadrilateral are A(-2,3), B(3,2), C(2,-1) and D(-3,0)

The slope of a line is given m=\frac{Y2-Y1}{X2-X1}

Now,

The slope of a line AB:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{2-3}{3-(-2)}

m=\frac{-1}{5}

The slope of a line BC:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{(-1)-2}{2-3}

m=\frac{-3}{-1}

m=3

The slope of a line CD:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{0-(-1)}{(-3)-2}

m=\frac{-1}{5}

The slope of a line DA:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{3-0}{(-2)-(-3)}

m=3

The slope of the line AB and CD are the same

The slope of the line BC and DA are the same

Thus, The quadrilateral ABCD is a parallelogram

3 0
3 years ago
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